Hillary

Practice the problems of Math in Focus Grade 5 Workbook Answer Key Chapter 9 Multiplying and Dividing Decimals to score better marks in the exam.

Math in Focus Grade 5 Chapter 9 Answer Key Multiplying and Dividing Decimals

Math Journal

Solve. Show your work.

Question 1.
James has a square piece of paper. He wants to cut it into 20 strips of equal width. He says This piece of paper is about 48 centimeters wide.’ How can he find out the width of each strip without measuring? Is this width accurate?
Answer:
2.4 centimeter wide.
Explanation:
By dividing the 48 cm in to 20 equal strips of 2.4cm
\(\frac{48}{20}\) = 2.4

Is this width accurate?
Yes
Explanation:
The strip is equally divided without leaving any remainder.
\(\frac{48}{20}\) = 2.4 centimeter wide

Question 2.
James takes a ruler and measures the width of the piece of paper. He finds that the actual width is 48.8 centimeters. Find the width of each strip. How can you check if your answer is reasonable?
Answer:
2.44 cenimetres
Explanation:
The actual width is 48.8 centimeters
and it is cut in to 20 strips of equal pieces
\(\frac{48.8}{20}\) = 2.44 cm

Put on Your Thinking!

Challenging Practice

Solve. Show your work.

Question 1.
A plumber has two pipes. One pipe is 7 times as long as the other pipe. He cuts 2.2 meters from the longer pipe. The remaining length of this pipe is 3 times that of the shorter pipe. Find the length of the shorter pipe in meters.
Answer:
0.55 meters short.
Explanation:
One pipe is of length x
Other pipe length is 7x
7x – 2.2 =3x
7x – 3x = 2.2
4x = 2.2
x= 2.2
\(\frac{2.2}{4}\) = 0.55m

Question 2.
At a farmer’s market, 5 pounds of strawberries cost $21.50. At a supermarket, 3 pounds of the same quality strawberries cost $15.75.

a. Which is a better buy?
Answer:
At a farmer’s market is a better buy.
Explanation:
1 pound of strawberries cost $4.3
At farmer market,
5 pounds of strawberries cost $21.50
for 1 pound= \(\frac{21.50}{5}\) = $ 4.3
At supermarket
3 pounds of strawberries cost $15.75
for 1 pound= \(\frac{15.75}{3}\) = $ 5.25

b. How much can you save by buying 20 pounds of the strawberries that are the better buy?
Answer: $19
Explanation:
The difference between the farmer’s market cost and the supermarket cost is
$5.25 – $4.3 = $0.95 for one pound of strawberries
20 x $0.95 = $19
$19 save by buying 20 pounds of the strawberries that are the better buy

Put On Your Thinking!

Problem Solving

Solve. Show your work.

Question 1.
Sam buys 10 oranges and 11 apples for $10.05. The total cost of 1 orange and 1 apple is $0.94. How much does an apple cost?
Answer: $5.17
Explanation:
Cost of 1 orange and 1 apple is $0.94
\(\frac{0.94}{2}\) = $ 0.47
an apple cost = 11 * $0.47= $5.17

Question 2.
A bucket filled with sand has a mass of 11.15 kilograms. When it is filled with water, the mass is 5.95 kilograms. The mass of the sand is twice that of the water. Find the mass of the bucket in grams.
Answer: 400 grams
Explanation:
Mass of bucket filled with sand is 11.5 kg
Mass of bucket filled with water is 5.95 kg
It is given that the mass of sand is twice that of the water.
So if mass of water is x kg, then mass of sand is 2x kg.
Let the mass of bucket be y kg, then as per given condition we get,  
 2x+y=11.5    ....(1)     
x+ y=5.95    ..….(2)
Subtract (2)  from (1)   
 2x+y=11.5      x+ y=5.95    −   −    −               x=5.55
Put this value in (2) to get,   
5.55+y=5.95        y=5.95−5.55        y=0.4
So the mass of bucket in grams is     0.4×1000=400 grams.

Solve. Show your work.

Question 3.
The total capacity of 6 pitchers and 12 glasses is 21 liters. The capacity of a pitcher is 5 times that of a glass. Find the capacity of each glass. Give your answer in liters.
Answer:
The capacity of each glass is 0.5 liters.
Explanation:
one picture = 5 glass
Total capacity = 6 pitchers + 12 glasses = 21 liters
= 30 glasses + 12 glasses = 21 liters
= 42 glasses = 21 liters
So, 21/42 = 0.5 liters.

Solve. Show your work.

Question 4.
Dahlia has just enough money to buy either 6 pears and 20 oranges or 12 oranges and 11 pears. A pear costs $0.80. How much does an orange cost?
Answer:
Orange cost is $0.5
Explanation:
let Pear is p and Orange is q
6p + 20q = 11p + 12q
11p – 6p = 20q – 12q
5p = 8q
q = 5p/8
q =  5 x 0.80 / 8
q = $0.50

Practice the problems of Math in Focus Grade 5 Workbook Answer Key Chapter 10 Practice 1 Percent to score better marks in the exam.

Math in Focus Grade 5 Chapter 10 Practice 1 Answer Key Percent

Each large square is divided into 100 parts. Fill in the blanks to describe each large square.

Question 1.

___ out of 100 equal parts are shaded.
___ % of the large square is shaded.
___ out of 100 equal parts are not shaded.
____ % of the large square is not shaded.
Answer:
46 out of 100 equal parts are shaded.
46 % of the large square is shaded.
54 out of 100 equal parts are not shaded.
54 % of the large square is not shaded.
Explanation:
Each large scale is divided into 100 squares,
out of which 46 are shaded and 54 are not shaded.
So the percentage of large scale are 46%  and 54%

Question 2.

___ out of 100 equal parts are shaded.
___ % of the large square is shaded.
___ out of 100 equal parts are not shaded.
____ % of the large square is not shaded.
Answer:
78 out of 100 equal parts are shaded.
78 % of the large square is shaded.
22 out of 100 equal parts are not shaded.
22 % of the large square is not shaded.
Explanation:
Each large scale is divided into 100 squares,
out of which 78 are shaded and 22 are not shaded.
So the percentage of large scale are 78%  and 22%

Express each decimal as a percent

Example
\(\frac{38}{100}\) = 38%

Question 3.
\(\frac{7}{100}\) = ___ %
Answer:
7%
Explanation:
To convert a fraction to a percent,
first divide the numerator by the denominator.
Then multiply the decimal by 100.
The fraction \(\frac{7}{100}\) can be converted to decimal by dividing 7 by 100.
It can be converted to percent by multiplying the decimal by 100.
7 ÷ 100 = 0.07×100 = 7
So, the fraction \(\frac{7}{100}\) is equivalent to 7%

Question 4.
\(\frac{7}{100}\) = ___ %
Answer:
7%
Explanation:
To convert a fraction to a percent,
first divide the numerator by the denominator.
Then multiply the decimal by 100.
The fraction \(\frac{7}{100}\) can be converted to decimal by dividing 7 by 100.
It can be converted to percent by multiplying the decimal by 100.
7 ÷ 100 = 0.07×100 = 7
So, the fraction \(\frac{7}{100}\) is equivalent to 7%

Question 5.
\(\frac{19}{100}\) = ___ %
Answer:
19%
Explanation:
To convert a fraction to a percent,
first divide the numerator by the denominator.
Then multiply the decimal by 100.
The fraction \(\frac{19}{100}\) can be converted to decimal by dividing 19 by 100.
It can be converted to percent by multiplying the decimal by 100.
19 ÷ 100 = 0.19×100 = 19
So, the fraction \(\frac{19}{100}\) is equivalent to 19%

Question 6.
\(\frac{6}{10}\) = ___ %
Answer:
60%
Explanation:
To convert a fraction to a percent,
first divide the numerator by the denominator.
Then multiply the decimal by 100.
The fraction \(\frac{6}{10}\) can be converted to decimal by dividing 6 by 10.
It can be converted to percent by multiplying the decimal by 100.
6 ÷ 10 = 0.6×100 = 60
So, the fraction \(\frac{6}{10}\) is equivalent to 60%

Question 7.
\(\frac{4}{10}\) = ___ %
Answer:
40%
Explanation:
To convert a fraction to a percent,
first divide the numerator by the denominator.
Then multiply the decimal by 100.
The fraction \(\frac{4}{10}\) can be converted to decimal by dividing 4 by 10.
It can be converted to percent by multiplying the decimal by 100.
4 ÷ 10 = 0.4×100 = 40
So, the fraction \(\frac{4}{10}\) is equivalent to 40%

Express each decimal as a percent.

Example

Question 8.

Answer: 28%
Explanation:
To convert a decimal to a fraction, place the decimal number over its place value.
First divide the numerator by the denominator.
Then multiply the decimal by 100, to convert a fraction to a percent.

Question 9.
0.07 = _________%
Answer: 7%
Explanation:
To convert a decimal to a fraction, place the decimal number over its place value.
First divide the numerator by the denominator.
Then multiply the decimal by 100, to convert a fraction to a percent.

Question 10.
0.01 = _________%
Answer: 1%
Explanation:
To convert a decimal to a fraction, place the decimal number over its place value.
First divide the numerator by the denominator.
Then multiply the decimal by 100, to convert a fraction to a percent.

Question 11.
0.08 _________%
Answer: 8%
Explanation:
To convert a decimal to a fraction, place the decimal number over its place value.
First divide the numerator by the denominator.
Then multiply the decimal by 100, to convert a fraction to a percent.

Question 12.
0.5 = _________%
Answer: 50%
Explanation:
To convert a decimal to a fraction, place the decimal number over its place value.
First divide the numerator by the denominator.
Then multiply the decimal by 100, to convert a fraction to a percent.

Question 13.
0.9 = _________%
Answer: 90%
Explanation:
To convert a decimal to a fraction, place the decimal number over its place value.
First divide the numerator by the denominator.
Then multiply the decimal by 100, to convert a fraction to a percent.

Question 14.
0.8 = _________%
Answer: 80%
Explanation:
To convert a decimal to a fraction, place the decimal number over its place value.
First divide the numerator by the denominator.
Then multiply the decimal by 100, to convert a fraction to a percent.

Express each percent as a fraction with a denominator of 100.

Example

Question 15.

Answer:

Explanation:
To convert a percent to a fraction,
we have to remove the percent sign and divide the given number by 100.

Question 16.

Answer:

Explanation:
To convert a percent to a fraction,
we have to remove the percent sign and divide the given number by 100.

Question 17.

Answer:

Explanation:
To convert a percent to a fraction,
we have to remove the percent sign and divide the given number by 100.

Question 18.

Answer:

Explanation:
To convert a percent to a fraction,
we have to remove the percent sign and divide the given number by 100.

Question 19.

Answer:

Explanation:
To convert a percent to a fraction,
we have to remove the percent sign and divide the given number by 100.

Express each percent as a fraction with a denominator of 100.

Example

Question 20.

Answer:

Explanation:
To convert a percent to a fraction,
we have to remove the percent sign and divide the given number by 100.
And, then we express the fractional form of the percentage in the simplest form.

Question 21.

Answer:

Explanation:
To convert a percent to a fraction,
we have to remove the percent sign and divide the given number by 100.
And, then we express the fractional form of the percentage in the simplest form.

Question 22.

Answer:

Explanation:
To convert a percent to a fraction,
we have to remove the percent sign and divide the given number by 100.
And, then we express the fractional form of the percentage in the simplest form.

Question 23.
46% =
Answer:

Explanation:
To convert a percent to a fraction,
we have to remove the percent sign and divide the given number by 100.
And, then we express the fractional form of the percentage in the simplest form.

Question 24.
55% =
Answer:

Explanation:
To convert a percent to a fraction,
we have to remove the percent sign and divide the given number by 100.
And, then we express the fractional form of the percentage in the simplest form.

Express each percent as a decimal.

Question 25.

Answer:

Explanation:
First remove the percent sign to convert from a percent to a decimal.
Divide the number by 100 and the out put is in the form of decimal.

Question 26.
9% = ___
Answer:

Explanation:
First remove the percent sign to convert from a percent to a decimal.
Divide the number by 100 and the out put is in the form of decimal.

Question 27.
1% = ___
Answer:

Explanation:
First remove the percent sign to convert from a percent to a decimal.
Divide the number by 100 and the out put is in the form of decimal.

Write each ratio as a fraction and then as a percent.

Question 28.

Answer:

Explanation:
Ratios are smaller to fractions, and each fraction can be written as a fraction.
Divide the first number 23 by the second number 100.
Multiply by 100 to convert to a percentage.
Add the percent symbol (%) to the output.

Question 29.

Answer:

Explanation:
Ratios are smaller to fractions, and each fraction can be written as a fraction.
Divide the first number 9 by the second number 100.
Multiply by 100 to convert to a percentage.
Add the percent symbol (%) to the output

Express each percent as a decimal. Then mark ✗ to show where each decimal is located on the number line.

Question 30.
71% = ______
Answer:

Explanation:
To convert a decimal to a percentage, multiply by 100,
just move the decimal point 2 places to the right.

Question 31.
19% = ___
Answer:

Explanation:
To convert a decimal to a percentage, multiply by 100,
just move the decimal point 2 places to the right.

Question 32.
44%= ____
Answer:

Explanation:
To convert a decimal to a percentage, multiply by 100,
just move the decimal point 2 places to the right.

Solve. Show your work.

Question 33.
There are 100 students in a drawing contest, and 58 of them are girls.
a. What percent of the students in the contest are girls?
Answer: 58%
Explanation:
To convert a fraction to a percent,
first divide the numerator by the denominator.
Then multiply the decimal by 100.
The fraction \(\frac{58}{100}\) can be converted to decimal by dividing 58 by 100.
It can be converted to percent by multiplying the decimal by 100.
58 ÷ 100 = 0.58×100 = 58
So, the fraction \(\frac{58}{100}\) is equivalent to 58%

b. What percent of the students in the contest are boys?
Answer: 42%
Explanation:
To convert a fraction to a percent,
first divide the numerator by the denominator.
Then multiply the decimal by 100.
The fraction \(\frac{42}{100}\) can be converted to decimal by dividing 42 by 100.
It can be converted to percent by multiplying the decimal by 100.
42 ÷ 100 = 0.42×100 = 42
So, the fraction \(\frac{42}{100}\) is equivalent to 42%

Question 34.
A jogging route is 10 kilometers long. Lee Ming has jogged 4 kilometers of the route.

a. What percent of the route has Lee Ming jogged?
Answer: 40%
Explanation:
A jogging route is 10 kilometers long.
Lee Ming has jogged 4 kilometers of the route.
To convert a fraction to a percent,
first divide the numerator by the denominator.
Then multiply the decimal by 100.
The fraction \(\frac{4}{10}\) can be converted to decimal by dividing 4 by 10.
It can be converted to percent by multiplying the decimal by 100.
4 ÷ 10 = 0.4×100 = 40
So, the fraction \(\frac{4}{10}\) is equivalent to 40%

b. What percent of the route does Lee Ming have to jog to complete the whole route?
Answer: 60%
Explanation:
A jogging route is 10 kilometers long.
Lee Ming has jogged 4 kilometers of the route.
To convert a fraction to a percent,
first divide the numerator by the denominator.
Then multiply the decimal by 100.
The fraction \(\frac{6}{10}\) can be converted to decimal by dividing 6 by 10.
It can be converted to percent by multiplying the decimal by 100.
6 ÷ 10 = 0.6×100 = 60
So, the fraction \(\frac{6}{10}\) is equivalent to 60%

This handy Math in Focus Grade 5 Workbook Answer Key Chapter 11 Practice 1 Making and Interpreting Double Bar Graphs provides detailed solutions for the textbook questions.

Math in Focus Grade 5 Chapter 11 Practice 1 Answer Key Making and Interpreting Double Bar Graphs

Complete. Use the data in the graph.

The double bar graph shows the number of boys and girls in two classes, 5A and 5B.

Question 1.
There are ___________ students in 5A and ___________ students in 5B.
Answer:
24 students in 5A and 20 students in 5B
Explanation:
The above graph shows number of boys and girls.
Number of students on y-axis and sections on y-axis.
number of boys in 5A = 10
number of girls in 5A = 14
total boys and girls in 5A = 10 + 14 = 24
Similarly,
number of boys in 5B = 10
number of girls in 5B = 10
total boys and girls in 5B = 10 + 10 = 20

Question 2.
There are ___________ more girls than boys in 5A.
Answer:
4 more girls than boys in 5A
Explanation:
number of boys in 5A = 10
number of girls in 5A = 14
number of more girls than boys in 5A = 14 – 10 = 4

Question 3.
Class ___________ has an equal number of boys and girls.
Answer:
5B has an equal number of boys and girls
Explanation:
The above graph shows number of boys and girls.
number of boys in 5B = 10
number of girls in 5B = 10
total boys and girls in 5B = 10 + 10 = 20

Question 4.
There are ___ girls altogether in 5A and 5B.
Answer:
24 girls altogether in 5A and 5B
Explanation:
The above graph shows number of boys and girls.
number of girls in 5A = 14
number of girls in 5B = 10
total girls in 5A and 5B = 14 + 10 = 24

Question 5.
There are ___ boys altogether in 5A and 5B.
Answer:
20 boys altogether in 5A and 5B
Explanation:
The above graph shows number of boys and girls.
number of boys in 5A = 10
number of boys in 5B = 10
total boys in 5A and 5B = 10 + 10 = 20

Question 6.
The average number of students in the two classes is ___
Answer: 22
Explanation:
The average number of students in the two classes is = 22
Average = sum/number of events
Average = \( \frac {24 + 20} {2} \)
= \( \frac {44} {2} \)
= 22

Complete the bar graph using the data in the table. Then answer the questions.

Question 7.
The table shows the number of bags of apples and oranges sold by a grocer on three days.

Answer:

Explanation:
The above graph shows number of apples and oranges sold on Thursday, Friday and Saturday.
y-axis represents the number of bags of apples and oranges.
x-axis represents the apples and oranges sold on particular days.

Question 8.
On Friday, ___ more bags of oranges than apples were sold.
Answer:
On Friday 15 more bags of oranges than apples were sold.
Explanation:
The above graph shows number of apples and oranges sold on Friday.
number of apples sold = 20
number of oranges sold = 35
number of more bags of oranges than apples = 35 – 20 = 15

Question 9.
On Saturday, ___ fewer bags of apples than oranges were sold.
Answer:
On Saturday, 20 fewer bags of apples than oranges were sold.
Explanation:
The above graph shows number of apples and oranges sold on Saturday.
number of apples sold = 25
number of oranges sold = 55
number of less bags of apples than oranges = 45 – 25 = 20

Question 10.
The total number of bags of apples and oranges sold was the greatest on ___________.
Answer:
The total number of bags of apples and oranges sold was the greatest on Saturday.
Explanation:
The above graph shows number of apples and oranges sold on Thursday, Friday and Saturday.
Comparing on the three days apples and oranges were sold more on Saturday.

Question 11.
The difference between the number of bags of apples and oranges sold was the least on ____.
Answer:
The difference between the number of bags of apples and oranges sold was the least on Thursday.
Explanation:
The above graph shows number of apples and oranges sold on Thursday, Friday and Saturday.
Comparing on the three days apples and oranges were sold less on Thursday.

This handy Math in Focus Grade 5 Workbook Answer Key Chapter 12 Practice 3 Vertical Angles provides detailed solutions for the textbook questions.

Math in Focus Grade 5 Chapter 12 Practice 3 Answer Key Vertical Angles

Complete.

Question 1.
\(\overleftrightarrow{A B}\) and \(\overleftrightarrow{C D}\) meet at O. Use a protractor to find unknown angle measure

m∠w = _______
m∠x = __________
m∠y = _____
m∠z = __________
m∠____ = m∠______
∠___________ and ∠___________ are vertical angles.
m∠____ = m∠______
∠___________ and ∠___________ are vertical angles.
Answer:
m∠w = 50°
m∠x = 130° = 180 ° – 50°
m∠y = 50°
m∠z = 130°
m∠w = m∠y
Vertical angles are a pair of opposite angles formed by intersecting lines
∠w  and ∠y are vertical angles.
m∠x = m∠z
∠x  and ∠z are vertical angles.
Explanation:
As can be seen from the figure above, when two lines intersect, four angles are formed.
Each opposite pair are called vertical angles and are always congruent.

Question 2.
\(\overleftrightarrow{X Z}\) and \(\overleftrightarrow{V W}\) meet at Y. Use a protractor to find unknown angle measures.

m∠XYW = _______
m∠WYU = __________
m∠UYZ = _____
m∠ZYV = __________
m∠VYX = ______
∠___________ and ∠___________ are vertical ongles.
∠___________ and ∠___________ are vertical angles.
Answer:

m∠XYW = 40°
m∠WYU = 90°
m∠UYZ = 50°
m∠ZYV = 40°
m∠VYX = 140°
∠XYW and ∠VYZ are vertical ongles.
∠WYZ and ∠XYV are vertical angles.
Explanation:
As can be seen from the figure above, when two lines intersect, four angles are formed.
Each opposite pair are called vertical angles and are always congruent.

Complete.

Question 3.
Look at the star and its marked angles. In the table below, write three sets of:
a. angles on a line,
b. angles at a point,
c. vertical angles.


Answer:

Draw.

Explanation:
The common point where two rays meet is called the vertex and the rays are called arms of the angle or Angle on lines.
Angles on line add upto 180°
An angle is measured with reference to a circle with its center at the common endpoint of the rays.
Hence, the sum of angles at a point is always 360°
When two lines intersect, four angles are formed.
Each opposite pair are called vertical angles and are always congruent.

Question 4.
Draw rays at P to form
a. an angle whose measure forms a sum of 180° with the measure of ∠x,
Answer:
x= 30°
30° x 6 = 180°

Explanation:
The common point where two rays meet is called the vertex and the rays are called arms of the angle or Angle on lines.
Angles on line add upto 180°

b. an angle whose measure is equal to the measure of ∠x.
(Do not use a protractor to draw the angles.)

a.

b.
Answer: 30°
Explanation:
An angle measures less than 90 degrees is called acute angle.

Find the unknown angle measures.

Question 5.
\(\overleftrightarrow{A B}\) and \(\overleftrightarrow{C D}\) meet at O. Find the measure of ∠COB.

Answer:
m∠COB = 130°

Explanation:
180 – 130 = 50°
Vertical angles are a pair of opposite angles formed by intersecting lines.
∠AOD  and ∠COB are vertical angles.
m∠AOD = m∠COB = 130°

Question 6.
\(\overleftrightarrow{E F}\) and \(\overleftrightarrow{G H}\) meet at O. Find the measures of ∠GOF and ∠EOH.

Answer:
m∠GOF = 132° and
m∠EOH = 132°
Explanation:

180° – 48° = 132°
Vertical angles are a pair of opposite angles formed by intersecting lines
∠GOF  and ∠EOH are vertical angles.
m∠GOF = m∠EOH = 132°

Question 7.
\(\overleftrightarrow{R S}\) and \(\overleftrightarrow{P Q}\) meet at N. Find the measures of ∠PNR, ∠RNQ, and ∠QNS.

Answer:
m∠PNR = 20°
m∠RNQ = 160°
m∠QNS = 20°
Explanation:
∠PNR = 180° – 160° = 20°
Vertical angles are a pair of opposite angles formed by intersecting lines

Find the unknown angle measures.

Question 8.
\(\overleftrightarrow{J K}\) and \(\overleftrightarrow{L M}\) meet at O. Find the measure of ∠NOK.

Answer:
∠NOK = 56°
Explanation:

∠LOJ = 180° – 108° = 72°
∠NOK = 180° -(52° + 72°)
=180° – 124°
=56°

Question 9.
\(\overleftrightarrow{A B}\), \(\overleftrightarrow{C D}\) and \(\overleftrightarrow{E F}\) meet at O. Find the measure of ∠x.

Answer:
m∠x = 120°
Explanation:
As can be seen from the figure below, when two lines intersect, four angles are formed.
Each opposite pair are called vertical angles and are always congruent.
∠AOF and ∠EOB are vertical angles

Question 10.
\(\overleftrightarrow{A B}\) and \(\overleftrightarrow{C D}\) meet at O. Find the measure of ∠w.

Answer:
m∠w = 75°
Explanation:

As can be seen from the figure above, when two lines intersect, four angles are formed.
Each opposite pair are called vertical angles and are always congruent.

Find the unknown angle measures.

Question 11.
\(\overleftrightarrow{Q R}\) and \(\overleftrightarrow{S T}\)meet at O. Find the measures of ∠QOS, ∠TOR, and ∠SOR.

Answer:
m∠QOS = 20°
m∠TOR= 20°
m∠SOR = 160°
Explanation:
As can be seen from the figure below, when two lines intersect, four angles are formed.
Each opposite pair are called vertical angles and are always congruent.

Question 12.
\(\overleftrightarrow{A B}\) and \(\overleftrightarrow{C D}\)meet at O. Find the measures of ∠p, ∠q, and ∠r.

m∠p = ____
m∠q = ____
m∠r = ____
Answer:
m∠p = 25°
m∠q = 155°
m∠r = 65°
Explanation:
As can be seen from the figure below, when two lines intersect, four angles are formed.
Each opposite pair are called vertical angles and are always congruent.

Question 13.
\(\overleftrightarrow{U V}\), \(\overleftrightarrow{W X}\), and \(\overleftrightarrow{Y Z}\) meet at O. Find the measure of ∠UOW.

Answer:

Explanation:
when two lines intersect, four angles are formed.
Each opposite pair are called vertical angles and are always congruent.
68° + 72° = 140
∠UOW = 180° -140° = 40°

Question 14.
\(\overleftrightarrow{A B}\), \(\overleftrightarrow{C D}\), and \(\overleftrightarrow{E F}\) meet at O. Find the measures of ∠x and ∠y.

Answer:
m∠x = 30°
m∠y = 60°
Explanation:
∠AOB  = 180° – (∠AOC + ∠FOB)
= 180° – (90° + 60°)
= 180° – 150° = 30°

Go through the Math in Focus Grade 5 Workbook Answer Key Chapter 2 Practice 2 Multiplying by Tens, Hundreds, or Thousands to finish your assignments.

Math in Focus Grade 5 Chapter 2 Practice 2 Answer Key Multiplying by Tens, Hundreds, or Thousands

Multiply.

Question 1.
47 × 10 = ___
Answer:
47 X 10 = 470,

Explanation:
Given 47 multiplied by 10 we get zero at units place and
we increment towards left side as shown,
so 47 X 10 = 470.

Question 2.
38 × 10 = ___
Answer:
38 X 10 = 380,

Explanation:
Given 38 multiplied by 10 we get zero at units place and
we increment towards left side as shown,
so 38 X 10 = 380.

Question 3.
109 × 10 = ___
Answer:
109 X 10 = 1,090,

Explanation:
Given 109 multiplied by 10 we get zero at units place and
we increment towards left side as shown,
so 109 X 10 = 1,090.

Question 4.
521 × 10 = ___
Answer:
521 X 10 = 5,210,

Explanation:
Given 521 multiplied by 10 we get zero at units place and
we increment towards left side as shown,
so 521 X 10 = 5,210.

Question 5.
7,140 × 10 = ___
Answer:
7,140 X 10 = 71,400,

Explanation:
Given 7,140 multiplied by 10 we get zero at units place and
we increment towards left side as shown,
so 7,140 X 10 = 71,400.

Question 6.
1,503 × 10 = ___
Answer:
1,503 X 10 = 15,030,

Explanation:
Given 1,503 multiplied by 10 we get zero at units place and
we increment towards left side as shown,
so 1,503 X 10 = 15,030.

Question 7.
3,702 × 10 = ___
Answer:
3,702 X 10 = 37,020,

Explanation:
Given 3,702 multiplied by 10 we get zero at units place and
we increment towards left side as shown,
so 3,702 X 10 = 37,020.

Question 8.
9,342 × 10 = ___
Answer:
9,342 X 10 = 93,420,

Explanation:
Given 9,342 multiplied by 10 we get zero at units place and
we increment towards left side as shown,
so 9,342 X 10 = 93,420.

Find the missing factors.

Question 9.
96 × __ = 960
Answer:
96 X __10__ = 960,

Explanation:
As given 96 X _____ = 960 to find missing factors we divide
960 by 96 we get 10, so answer is 96 X __10 ___ = 960.

Question 10.
___ × 10 = 700
Answer:
__70 __ X 10 = 700,

Explanation:
As given  _____ X 10 = 700 to find missing factors we divide
700 by 10 we get 70, so answer is  __70 _ X 10 = 700.

Question 11.
514 × __ = 5,140
Answer:
514 X __10 __= 5,140,

Explanation:
As given 514 X _____ = 5,140 to find missing factors we divide
5,140 by 514 we get 10, so answer is 514 X __10 ___ = 5,140.

Question 12.
___ × 10 = 5,000
Answer:
__500 __ X 10 = 5,000,

Explanation:
As given  _____ X 10 = 5,000 to find missing factors we divide
5,000 by 10 we get 500, so answer is  __500_ X 10 = 5,000.

Question 13.
308 × ___ = 3,080
Answer:
308 X __10_ = 3,080,

Explanation:
As given 308 X _____ = 3,080 to find missing factors we divide
308 by 3,080 we get 10, so answer is 308 X __10 ___ = 3,080.

Question 14.
___ × 10 = 4,020
Answer:
__402__ X 10 = 4,020,

Explanation:
As given _____ X 10 = 4,020 to find missing factors we divide
4,020 by 10 we get 402, so answer is __402 ___ X 10 = 4,020.

Question 15.
2,096 × ___ = 20,960
Answer:
2,096 X __10 ___ = 20,960,

Explanation:
As given 2,096 X _____ = 20,960 to find missing factors we divide
20,960 by 2,096 we get 10, so answer is 2,096 X __10 ___ = 20,096.

Question 16.
___ × 10 = 91,760
Answer:
__9,176__ X 10 = 91,760,

Explanation:
As given _____ X 10 = 91,760 to find missing factors we divide
91,760 by 10 we get 9,176, so answer is __9,176 ___ X 10 = 91,760.

Complete.

Example.

65 × 40 = (65 × 4) × 10
= 260 × 10
= 2,600
Answer:
65 X 40 = 2,600,

Explanation:
Given 65 X 40  as 40 can be divided as 4 X 10,
So (65 X _4_) X 10,
__260__ X 10,
_2,600_,
therefore 65 X 40 = 2,600.

Question 17.
39 × 30
= (39 × _3__) × 10
= _117_ × 10
= _1,170___
Answer:
39 X 30 = 1,170,

Explanation:
Given 39 X 30 as 30 can be divided as 3 X 10,
So (39 X _3_) X 10,
__117__ X 10,
_1,170_,
therefore 39 X 30 = 1,170.

Question 18.
143 × 90
= (143 × _9_) × __10__
= __1,287__ × __10__
= _12,870___
Answer:
143 X 90 = 12,870,

Explanation:
Given 143 X 90 as 90 can be divided as 9 X 10,
So (143 X _9_) X 10,
__1,287__ X 10,
_12,870_,
therefore 143 X 90 = 12,870.

Question 19.
360 × 30
= (360 × _3__) × __10__
= _1,080__ × __10__
= __10,800__
Answer:
360 X 30 = 10,800,

Explanation:
Given 360 X 3 as 30 can be divided as 3 X 10,
So(360 X _3_) X 10,
__1,080__ X 10,
_10,800_,
therefore 360 X 30 = 10,800.

Question 20.
285 × 80
= (285 × _8_) × _10__
= _2,280___ × _10__
= _22,800__
Answer:
285 X 80 = 22,800,

Explanation:
Given 285 X 80 as 80 can be divided as 8 X 10,
So(285 X _8_) X 10,
__2,280__ X 10,
_22,800_,
therefore 39 X 30 = 1,170.

Multiply.

Question 21.
7 × 1,000 = ___
Answer:
7,000 ,

Explanation:
Given to find multiplication of 7 with thousand we get
7,000 .

Question 22.
86 × 100 = ___
Answer:
8,600

Explanation:
Given to find multiplication of 86 with hundred we get
8,600 .

Question 23.
70 × 1,000 = ___
Answer:
70,000 ,

Explanation:
Given to find multiplication of 70 with thousand we get
70,000.

Question 24.
95 × 100 = __
Answer:
9,500,
Explanation:
Given to find multiplication of 9,500 with hundred we get
9,500.

Question 25.
400 × 1,000 = ____4,00,000_____
Answer:
4,00,000 ,

Explanation:
Given to find multiplication of 400 with thousand we get
4,00,000.

Question 26.
217 × 100 = ___21,700_____
Answer:
21,700,

Explanation:
Given to find multiplication of 217 with hundred we get
217 X 100 = 21,700.

Question 27.
726 × 1,000 = ___72,60,000______

Answer:
72,60,000 ,

Explanation:
Given to find multiplication of 726 with thousand we get
72,60,000 .

Question 28.
803 × 100 = _____80,300____
Answer:
80,300 ,

Explanation:
Given to find multiplication of 803 with hundred we get
80,300.

Question 29.
8,032 × 1,000 = ____80,32,000_______
Answer:
80,32,000 ,

Explanation:
Given to find multiplication of 8,032 with thousand we get
80,32,000.

Question 30.
3,810 × 100 = ___3,81,000______
Answer:
3,81,000,

Explanation:
Given to find multiplication of 3,810 with hundred we get
3,81,000 .

Question 31.
3,936 × 1,000 = ___39,36,000________
Answer:
39,36,000 ,

Explanation:
Given to find multiplication of 3,936 with thousand we get
39,36,000.

What cat has long, fine hair, and a snubbed nose?
Write the letters that match the answers below to find out.

PERSIAN cat has long, fine hair and a snubbed nose,

Explanation:
Persian cat has long, fine hair, and a snubbed nose,
the letters that match the answers above are written above as
P – 21,700,
E – 9,500,
R – 7,000,
S – 80,300,
I – 7,26,000,
A – 70,000,
N – 3,936,000.

Find the missing factors.

Question 32.
17 × ___100____ = 1,700

Answer:
17 X 100 = 1,700,

Explanation:
Given 17 X ____ = 1,700,
to find missing factor we divide 1,700 by 17 we get
1,700 ÷ 17 = 100.

Question 33.
_25__ × 1,000 = 25,000
Answer:
__25__ X 1,000 = 25,000,

Explanation:
Given ____ X 1,000 = 25,000,
to find missing factor we divide 25,000 by 1,000 we get
25,000 ÷ 1,000 = 25.

Question 34.
____4,78_____ × 1,000 = 4,78,000
Answer:
__4,78___ X 1,000 = 4,78,000,

Explanation:
Given ____ X 1,000 = 4,78,000,
to find missing factor we divide 4,78,000 by 1,000 we get
4,78,000 ÷ 1,000 = 4,78.

Question 35.
320 × _1,000_ = 3,20,000
Answer:
320 X __1,000__ = 3,20,000,

Explanation:
Given 320 X __1,000___ = 3,20,000,
to find missing factor we divide 3,20,000 by 320 we get
3,20,000 ÷ 320 = 1,000.

Question 36.
1,315 × ____100____ = 131,500
Answer:
1,315  X __100___ = 131,500,

Explanation:
Given 1,315 X _ 100_ = 131,500
to find missing factor we divide 131,500 by 1,315 we get
131,500 ÷ 1,315 = 100.

Question 37.
_2,662__ × 1,000 = 2,662,000
Answer:
__2,662__ X 1,000 = 2,662,000,

Explanation:
Given ____ X 1,000 = 2,662,000,
to find missing factor we divide 2,662,000 by 1,000 we get
2,662,000 ÷ 1,000 = 2,662.

Question 38.
4,668 × ___100___ = 4,66,800
Answer:
4,668  X __100__ = 4,66,800,

Explanation:
Given 4,668 X _ 100_ = 4,66,800
to find missing factor we divide 4,668 by 100 we get
4,66,800 ÷ 4,668 = 100.

Question 39
___25_____ × 1,000 = 25,000
Answer:
__25___ X 1,000 = 25,000,

Explanation:
Given ____ X 1,000 = 25,000,
to find missing factor we divide 25,000 by 1,000 we get
25,000 ÷ 1,000 = 25.

Complete.

Example.
4 × 300 = (4 × 3) × 100
= 12 × 100
= 1,200

Question 40.
12 × 500 =
= (12 × _5__) × 100
= ___60___ × 100
= __6,000__
Answer:
12 X 500 = 6,000,

Explanation:
Given to find 12 X 500 so
=  (12 X __5__) X 100,
= __60__ X 100,
= __6,000_.

Question 41.
700 × 900 = (700 × __9_) × 1oo
= ___6,300___ × 100
= _6,30,000___
Answer:
700 X 900 = (700 X __9__) X 100,

Explanation:
Given to find 700 X 900 so
= (700 X __9__) X 100,
= ___6,300___ X 100,
= ___ 6,30,000__.

Complete.

Question 42.
814 × 700 =
= (814 × __7_) × 100
= __5,698____ × 100
= 5,69,800
Answer:
814 X 700 = 5,69,800,

Explanation:
Given to find 814 X 700 so
(814 X __7 __) X 100,
= __5,698___ X 100,
= 5,69,800.

Question 43.
5,400 × 800 =
= (5,400 × _8__) × 100
= __43,200____ × 100
= _4,320,000__
Answer:
5,400 X 800= 43,200,

Explanation:
Given to find 5,400 X 800 so
= __43,200__ X 100,
= __4,320,000__.

Question 44.
5 × 7,000
= (5 × _7_) × 1,000
= ___35____ × 1,000
= __35,000__
Answer:
5 X 7,000 = 35,000,

Explanation:
Given to find 5 X 7,000  so
= (5 X _7_) X 1,000,
= __35___ X 1,000,
= 35,000.

Question 45.
8 × 5,000
= (8 × _5_) × 1,000
= ___40___ × 1,000
= __40,000__
Answer:
8 X 5,000 = 40,000,

Explanation:
Given to find 8 X 5,000 so
= 8 X 5 X 1,000,
= 40 X 1,000,
= 40,000.

Question 46.
12 × 3,000
= (12 × __3_) × 1,000
= _36__ × 1,000
= __36,000___
Answer:
12 X 3,000 = 36,000,

Explanation:
Given to find 12 X 3,000 so
=(12 X __3__) X 1,000,
= __36__ X 1,000,
= __36,000__.

Question 47.
15 × 2,000
= (15 × __2_) × 1,000
= ___30____ × 1,000
= __30,000___
Answer:
15 X 2,000 = 30,000,

Explanation:
Given to find 15 X 2,000 so
15 X 2 X 1000,
= 30 X 1,000,
= 30,000.

Question 48.
300 × 4,000
= (300 × __4_) × _1,000___
= _1,200_ × 1,000
= _12,00,000___
Answer:
300 X 4,000 = 12,00,000,

Explanation:
Given to find 300 X 4,000 we get
300 x 4 X 1,000,
= 12,00 X 1,000,
=  12,00,000.

Question 49.
663 × 6,000
= (663 × _6_) × 1,000
= _3,978__ × 1,000
= _39,78,000___
Answer:
663 X 6,000 =39,78,000,

Explanation:
Given to find 663 X 6,000 so
663 X 6 X 1,000,
= 3,978 X 1,000,
= 39,78,000.

Multiply.

Question 50.

Answer:

Explanation:
Multiplying by Tens we get 17 X 70 as 17 X 7 X 10 = 1,190,
Multplying by Hundreds we get 17 X 700 as 17 X 7 X 100 = 11,900,
Multiplying by Thousands we get 17 X 7,000 = 17 X 7 X 1,000 = 1,19,000.

Question 51.

Answer:

Explanation:
Multiplying by Tens we get 65 X 30 as 65 X 3 X 10 = 1,950,
Multplying by Hundreds we get 65 X 300 as 65 X 3 X 100 = 19,500,
Multiplying by Thousands we get 65 X 3,000 = 65 X 3 X 1,000 = 1,95,000.

Question 52.

Answer:

Explanation:
Multiplying by Tens we get 90 X 40 as 9 X 4 X 10 = 3,600,
Multplying by Hundreds we get 90 X 400 as 90 X 4 X 100 = 36,000,
Multiplying by Thousands we get 90 X 4,000 = 90 X 4 X 1,000 = 3,60,000.

Question 53.

Answer:

Explanation:
Multiplying by Tens we get 812 X 10 as 812 X 10 = 8,120,
Multplying by Hundreds we get 812 X 100 as 812 X 100 = 81,200,
Multiplying by Thousands we get 812 X 1,000 = 812 X 1,000 = 8,12,000.

Question 54.

Answer:

Explanation:
Multiplying by Tens we get 634 X 20 as 634 X 2 X 10 = 12,680,
Multplying by Hundreds we get 634 X 200 as 634 X 2 X 100 = 1,26,800,
Multiplying by Thousands we get 634 X 200 = 634 X 2 X 1,000 = 12,68,000.

Find the missing factors.

Question 55.
31 × ___100_____ = 3,100
Answer:
31 X 100 = 3,100,

Explanation:
Given to find 31 X ___ = 3,100,
the missing factor is 3,100 ÷ 31 = 100.

Question 56.
30 × ___3,000______ = 90,000
Answer:
30 X ___3,000___ = 90,000,

Explanation:
Given to find 30 X _____ = 90,000,
So we divide 90,000 by 30 we get 90,000 ÷ 30 = 3,000.

Question 57.
103 × ___30_____ = 3,090
Answer:
103 X _30 ___ = 3,090,

Explanation:
Given to find 103 X _____ = 3,090,
So we divide 3,090 by 103 we get 3,090 ÷ 103  = 30.

Question 58.
25 × ____200_____ = 5,000
Answer:
25 X __200__ = 5,000,

Given to find 25 X _____ = 5,000,
So we divide 5,000 by 25 we get 5,000 ÷ 25 = 200.

The owner of on electronics store wants to estimate the amount she will receive from the soles of these items:

58 all-in-one printers at $219 each.
652 radio clocks at $73 each.
99 portable audio players at $217 each.
39 plasma television sets at $4,156 each.

Answer:
The owner of the electronics store will receive $19,38,025,

Explanation:
Given the owner of an electronics store wants to estimate the amount she
will receive from the soles of these items:
58 all-in-one printers at $219 each.
652 radio clocks at $73 each.
99 portable audio players at $217 each.
39 plasma television sets at $4,156 each are
So for all-in-one printers it is 58 X $219 = $12,702,
for radio clocks it is 652 X $73 = $47,596 for
portable audio players it is 99 X $217 = $21,483 and
for 39 plasma television sets it is 39 X $47,596 = $18,56,244.
Therefore the owner will receive
$12,702 + $47,596 + $21,483 + $18,56,244 = $19,38,025.

Estimate the amount she receives for each type of item by rounding to the greatest place value. Then, estimate the total amount from the sales of the items.

Question 59.
58 × $219 rounds to ___60______ × $___220______ = $4,400
Answer:
$4,400,

Explanation:
When 58 X $219 rounds to 60 X $220 we get $4,400.

Question 60.
652 × $73 rounds to ___650______ × $ ___70___ = $45,500
Answer:
$45,500,

Explanation:
When 652 X $73 rounds to 650 X $70 we get $45,500.

Question 61.
99 × $217 rounds to ____100______ × $ __220_______ = $22,000
Answer:
$22,000,

Explanation:
When 99 X $217 rounds to 100 X $220 we get $22,000.

Question 62.
39 × $4156 rounds to ___40______ × $ ___4,160______ = $1,66,400
Answer:
$1,66,400,

Explanation:
When 39 X $4156 rounds to 40 X $4,160 = $1,66,400.

Question 63.
The total estimated amount is
$ _4,400____ +$ __45,500___ +$ __22,000___ +$1,66,400
= $ _2,38,300_____
Answer:
$2,38,300,

Explanation:
The given total estimated amount is $4,400 + $45,500 + $22,000 + $1,66,400 =
$2,38,300,

This handy Math in Focus Grade 1 Workbook Answer Key Cumulative Review Chapters 3 and 4 detailed solutions for the textbook questions.

Math in Focus Grade 1 Cumulative Review Chapters 3 and 4 Answer Key

Concepts and Skills

Look at the pictures. Complete the number sentences.

Question 1.

Answer:

Explanation:
8 breads are colored and baked 2 breads are not colored and baked
so, total number of breads baked are = 8 + 2 = 10

Question 2.

Answer:

Explanation:
In a ten frame there are 9 dots in that 4 are crossed
so, 9 – 4 = 5

Complete the number bonds. Fill in the blanks.

Question 3.
___ + 5 = 10

Answer:

Explanation:
The sum of 5 and 5 is 10
that is stated by number bond

Question 4.
8 – 3 = ___

Answer:

Explanation:
The difference of 8 and 3 is 4
that is stated by number bond

Fill in the blanks.

Question 5.
2 more than 8 is ____
Answer:
10
Explanation:
2 more than 8 is number 10
2 + 8 = 10

Question 6.
3 less than 7 is ___.
Answer:
4
Explanation:
3 less than 7 is number 4
7 – 3 = 4

Question 7.
_______ is 2 more than 5.
Answer:
7
Explanation:
2 + 5 = 7
number 7 is 2 more than 5.

Question 8.
________ is 5 less than 10.
Answer:
5
Explanation:
10 – 5 = 5
number 5 is 5 less than 10.

Find the missing number.
Use related facts to help you.

Question 9.
2 + ______ = 8
Answer:
6
Explanation:
The sum of 2 and 6 is 8
2 + 6 = 8

Question 10.
______ – 6 = 0
Answer:
6
Explanation:
6 – 6 = 0
The difference of 6 and 6 is 0

Pick three numbers and make a fact family.

Question 11.

Answer:

Explanation:

Problem Solving
Look at the pictures.
Write an addition or subtraction story.

Question 12.

Answer:

Explanation:
There are different shapes of buttons
in them 5 are colored and 4 are non colored
so, total number of buttons are 9
5 + 4 = 9

Question 13.

Answer:

Explanation:
Jamel is catching 9 balloons
3 flew away
so, 9 – 3 = 6
6 are left.

Solve.

Write addition or subtraction sentences.

Question 14.
Ellen has 3 spoons. Her sister gives her 5 spoons. How many spoons does Ellen have now?

Ellen has ___ spoons now.
Answer:

Explanation:
Ellen has 3 spoons. Her sister gives her 5 spoons.
Ellen has 8 spoons now.
3 + 5 = 8

Question 15.
There are 8 fish in a fish tank. 6 are angelfish and the rest are goldfish. How many goldfish are there?

There are ___ goldfish.
Answer:

Explanation:
There are 8 fish in a fish tank. 6 are angelfish and the rest are goldfish.
8 – 6 = 2
There are 2 goldfish.

Go through the Math in Focus Grade 1 Workbook Answer Key Chapter 16 Practice 3 Comparing, Ordering, and Patterns to finish your assignments.

Math in Focus Grade 1 Chapter 16 Practice 3 Answer Key Comparing, Ordering, and Patterns

Find the missing numbers.

Example

2 more than 50 is 52.
2 less than 66 is 64.

Question 1.
2 more than 54 is ____________.
Answer:
2 more than 54 is 56.

Explanation:
Given that 2 more than 54 which is 54+2 = 56.

Question 2.
______________ is 2 more than 66.
Answer:
68 is 2 more than 66.

Explanation:
Given that 2 more than 66 which is 66+2 = 68.

Question 3.
2 less than 78 is ______________.
Answer:
2 less than 78 is 76.

Explanation:
Given that 2 less than 78 which is 78-2 = 76.

Question 4.
____________ is 2 less than 74.
Answer:
72 is 2 less than 74.

Explanation:
Given that 2 less than 74 which is 74-2 = 72.

Question 5.
5 more than 50 is ______________.
Answer:
5 more than 50 is 55.

Explanation:
Given that 5 more than 50 which is 50+5 = 55.

Question 6.
10 more than 85 is ______________.
Answer:
10 more than 85 is 95.

Explanation:
Given that 10 more than 85 which is 95.

Question 7.
5 less than 65 is ______________.
Answer:
5 less than 65 is 60.

Explanation:
Given that 5 less than 65 which is 65-5 = 60.

Question 8.
____________ is 10 less than 100.
Answer:
10 less than 100 is 90.

Explanation:
Given that 10 less than 100 which is 100-10 = 90.

Question 9.
____________ is 5 more than 75.
Answer:
5 more than 75 is 80.

Explanation:
Given that 5 more than 75 which is 80.

Question 10.
____________ is 5 less than 75.
Answer:
5 less than 75 is 70.

Explanation:
Given that 5 is less than 75 which is 70.

Circle the greatest number.

Question 11.
72 or 87
Answer:
87.

Explanation:
Given numbers are 72 and 87. So the greatest number is 87.

Question 12.
92 or 69
Answer:
92.

Explanation:
Given numbers are 92 and 69. So the greatest number is 92.

Question 13.
54 or 45
Answer:
54.

Explanation:
Given numbers are 54 and 45. So the greatest number is 54.

Question 14.
67 or 76
Answer:
76.

Explanation:
Given numbers are 67 and 76. So the greatest number is 76.

Question 15.
86 or 83
Answer:
86.

Explanation:
Given numbers are 86 and 83. So the greatest number is 86.

Question 16.
94 or 98
Answer:
98.

Explanation:
Given numbers are 94 and 98. So the greatest number is 98.

Color the number that is less.

Question 17.

Answer:
59 is less than 71.

Explanation:
Given numbers are 59 and 71. The number 59 is less than 71.

Question 18.

Answer:
68 is less than 93.

Explanation:
Given numbers are 68 and 93. The number 68 is less than 93.

Question 19.

Answer:
79 is less than 97.

Explanation:
Given numbers are 79 and 97. The number 79 is less than 97.

Question 20.

Answer:
48 is less than 48.

Explanation:
Given numbers are 84 and 48. The number 48 is less than 84.

Question 21.

Answer:
62 is less than 67.

Explanation:
Given numbers are 62 and 67. The number 62 is less than 67.

Question 22.

Answer:

Explanation:
Given numbers are 96 and 91. The number 91 is less than 96.

Compare the numbers. Then fill in the blanks.

Question 23.

The least number is ___________.
The greatest number is __________.
Answer:
The least number is 49.
The greatest number is 72.

Explanation:
In the above image, the least number is 49 and the greatest number is 72.

Question 24.

The least number is ___________.
The greatest number is __________.
Answer:
The least number is 69.
The greatest number is 90.

Explanation:
In the above image, the least number is 69 and the greatest number is 90.

Question 25.
Order the numbers from greatest to least.

Answer:
99,89,54,45.

Explanation:
The numbers from greatest to least is 99,89,54,45.

Use the numbers to fill in the blanks.

Question 26.
The greatest number is __________.
Answer:
100.

Explanation:
The greatest number is 100.

Question 27.
The least number is __________.
Answer:
46.

Explanation:
The least number is 46.

Question 28.
__________, __________, and ________ are less than 84.
Answer:
46,67 and 73.

Explanation:
46,63 and 73 are less than 84.

Question 29.
____________ and __________ are greater than 84.
Answer:
92,100.

Explanation:
92 and 100 are greater than 84.

Question 30.
67 is greater than ___________ but less than 100.
Answer:
46.

Explanation:
67 is greater than 46 but less than 100.

Question 31.
92 is less than ___________ but greater than 84.
Answer:
100.

Explanation:
92 is less than 100 but greater than 84.

Complete each number pattern.

Question 32.
50, 51, 52, __________, 54, 55, __________, __________, 58
Answer:
50,51,52,53,54,55,56,57,58.

Explanation:
The complete pattern is 50,51,52,53,54,55,56,57,58.

Question 33.
73, 72, 71, __________, __________, 68, __________
Answer:
73,72,71,70,69,68,67.

Explanation:
The complete pattern is 73,72,71,70,69,68,67.

Question 34.
__________, 87, 89, __________, 93, __________
Answer:
85,87,89,91,93,95.

Explanation:
The complete pattern is 85,87,89,91,93,95.

Question 35.
99, __________, 95, 93, __________, __________
Answer:

Question 36.
50, 60, __________, 80, __________, __________
Answer:
50,60,70,80,90,100.

Explanation:
The complete pattern is 50,60,70,80,90,100.

Question 37.
93, 83, 73, __________, __________, 43, __________
Answer:
93,83,73,63,53,43,33.

Explanation:
The complete pattern is 93,83,73,63,53,43,33.

Practice the problems of Math in Focus Grade 3 Workbook Answer Key Chapter 14 Practice 1 Understanding Fractions to score better marks in the exam.

Math in Focus Grade 3 Chapter 14 Practice 1 Answer Key Understanding Fractions

Find the fractions that make a whole.

Example

\(\frac{2}{5}+\frac{3}{5}=\frac{5}{5}\)
= 1
Two-fifths and three-fifths make 1 whole.

Fill in the blanks.

Question 1.

___________ – ___________ and
___________ – ___________ make 1 whole.
Answer:

Five – sixths and one – sixths make 1 whole.
Explanation:
In the above image we can observe five parts are shaded with black color out of six parts and one part is unshaded out of 6 parts. To make 1 whole we need to add 5/6 with 1/6.

Question 2.

___________ – ___________, ___________ – ___________, and ___________ – ___________ make 1 whole.
Answer:

one – eights, two eights and five eights make 1 whole.
Explanation:
In the above image we can observe 1 part is shaded with white color out of eight parts and two parts are shaded with gray color out of eight parts, five parts are shaded with gray color out of 8 parts. To make 1 whole we need to add 1/8, and 2/8 with 5/8.

Name the numerator and denominator.

Example

\(\frac{4}{6}\) of the figure is shaded.
In this fraction, the numerator is 4.
In this fraction, the denominator is 6.

Complete.

Question 3.
of the figure is not shaded.
In this fraction, the numerator is ___________.
In this fraction, the denominator is ____________.
Answer:
 of the figure is not shaded.
In this fraction, the numerator is 4.
In this fraction, the denominator is 7.

Question 4.

of the figure is shaded.
In this fraction, the numerator is ____________.
In this fraction, the denominator is ____________.
Answer:
of the figure is shaded.
In this fraction, the numerator is 4.
In this fraction, the denominator is 8.

Practice the problems of Math in Focus Grade 3 Workbook Answer Key Chapter 10 Practice 1 Addition to score better marks in the exam.

Math in Focus Grade 3 Chapter 10 Practice 1 Answer Key Addition

Add mentally.

Question 1.
$7.30 + $2.00 = $__________
Answer:
$7.30 + $2.00 = $9.30
Explanation:
Perform addition operation on above two numbers. Add $7.30 with $2.00 the sum is $9.30.

Question 2.
$37.20 + $0.45 = $__________
Answer:
$37.20 + $0.45 = $37.65
Explanation:
Perform addition operation on above two numbers. Add $37.20 with $0.45 the sum is $37.65.

Question 3.
$5.20 + $12.65 = $__________
Answer:
$5.20 + $12.65 = $17.85
Explanation:
Perform addition operation on above two numbers. Add $5.20 with $12.65 the sum is $17.85.

Question 4.
$51.20 + $14.80 = $__________
Answer:
$51.20 + $14.80 = $66.00
Explanation:
Perform addition operation on above two numbers. Add $51.20 with $14.80 the sum is $66.00.

Question 5.
$0.95 + $9.35 = $__________
Answer:
$0.95 + $9.35 = $10.30
Explanation:
Perform addition operation on above two numbers. Add $0.95 with $9.35 the sum is $10.30.

Question 6.
$4.35 + $64.85 = $__________
Answer:
$4.35 + $64.85 = $69.20
Explanation:
Perform addition operation on above two numbers. Add $4.35 with $64.85 the sum is $69.20.

Question 7.
$31.65 + $3.90 = $__________
Answer:
$31.65 + $3.90 = $35.55
Explanation:
Perform addition operation on above two numbers. Add $31.65 with $3.90 the sum is $35.55.

Question 8.
$5.45 + $0.75 = $__________
Answer:
$5.45 + $0.75 = $6.20
Explanation:
Perform addition operation on above two numbers. Add $5.45 with $0.75 the sum is $6.20.

Find each missing amount.

Question 9.

$26 + $72 = $__________
40¢ + 50¢ = __________¢
$__________ + __________¢ = $__________
Answer:

$26 + $72 = $98
40¢ + 50¢ = 90¢
$98 + 90¢ = $98.90
Explanation:
In the above image we can observe before the decimal point the number is represented with $ and after the decimal point the number is represented with ¢. The total sum is represented with $.
Add before the decimal point numbers.
$26 + $72 = $98
Add after the decimal point numbers.
40¢ + 50¢ = 90¢
Add before and after decimal point numbers.
$98 + 90¢ = $98.90

Question 10.

$__________ + $__________ = $__________
__________¢ + __________¢ = __________¢
$__________ + __________¢ = $ __________
Answer:

$51 + $4= $55
25¢ +20¢ = 45¢
$55 + 45¢ = $ 55.45
Explanation:
In the above image we can observe before the decimal point the number is represented with $ and after the decimal point the number is represented with ¢. The total sum is represented with $.
Add before the decimal point numbers.
$51 + $4= $55
Add after the decimal point numbers.
25¢ +20¢ = 45¢
Add before and after decimal point numbers.
$55 + 45¢ = $ 55.45

Find each missing amount.

Question 11.

$__________ + $__________ = $__________
__________¢ + __________¢ = __________¢
$__________ + __________¢ = $ __________
Answer:

$6 + $18 = $24
5¢ + 20¢ = 25¢
$24 + 25¢ = $ 24.25
Explanation:
In the above image we can observe before the decimal point the number is represented with $ and after the decimal point the number is represented with ¢. The total sum is represented with $.
Add before the decimal point numbers.
$6 + $18 = $24
Add after the decimal point numbers.
5¢ + 20¢ = 25¢
Add before and after decimal point numbers.
$24 + 25¢ = $ 24.25

Question 12.

$__________ + $__________ = $__________
__________¢ + __________¢ = __________¢
$__________ + __________¢ = $ __________
Answer:

$60 + $17 = $77
5¢ + 70¢ = 75¢
$77 + 75¢ = $ 77.75
Explanation:
In the above image we can observe before the decimal point the number is represented with $ and after the decimal point the number is represented with ¢. The total sum is represented with $.
Add before the decimal point numbers.
$60 + $17 = $77
Add after the decimal point numbers.
5¢ + 70¢ = 75¢
Add before and after decimal point numbers.
$77 + 75¢ = $ 77.75

Use the items and prices in the picture to answer each exercise.

What is the cost of
Question 13.
a carton of milk and a head of broccoli? $ __________
Answer:
A carton of milk cost is $2.70.
A head of broccoli cost is $2.30
$2.70 + $2.30 = $ 5
The cost of both carton of milk and a head of broccoli are $5.

Question 14.
a bunch of grapes and a packet of whole meal biscuits? $__________
Answer:
A bunch of grapes cost is $12.95.
A packet of whole meal biscuits is $3.05.
$12.95 + $3.05 = $16
The cost of both bunch of grapes and a packet of whole meal biscuits are $16.

Question 15.
a cucumber and a head of cabbage? $__________
Answer:
A cucumber cost is $0.85
A head of cabbage cost is $1.15.
$0.85 + $1.15 = $2
The cost of both cucumber and a head of cabbage are $2.

Question 16.
a pack of cheese and a box of oranges? $__________
Answer:
A pack of cheese cost is $3.55.
A box of oranges cost is $9.45.
$3.55 + $9.45 = $13
The cost of both pack of cheese and a box of oranges are $13.

This handy Math in Focus Grade 1 Workbook Answer Key Chapter 6 Practice 2 Position Words detailed solutions for the textbook questions.

Math in Focus Grade 1 Chapter 6 Practice 2 Answer Key Position Words

Look at the picture. Circle the correct name.

Example
Who is after Alice? Carlo

Question 1.
Who is before Ben? Carlo Alice
Answer: Alice is before Ben.

Question 2.
Who is after Carlo? Ben Denelle
Answer: Denelle is after Carlo

Question 3.
Who is between Eddie and Carlo? Alice Denelle
Answer: Denelle is between Eddie and Carlo.

Question 4.
Who is between Carlo and Alice? Ben Eddie
Answer: Ben is between Carlo and Alice.

Color.

Example
the fourth bird from the left

Question 5.
the second pizza from the left

Answer:

Question 6.
the fifth monkey from the right

Answer:

Question 7.
the ninth football from the right

Answer:

Look at the picture. Fill in the blanks with the words in the box.

Question 8.
The long haired dog is first on the ____
Answer: The long haired dog is first on the left

Question 9.
The small dog is ___ from the left.
Answer: The small dog is fifth from the left.

Question 10.
The skinny dog is ___ the fat dog.
Answer: The skinny dog is next to the fat dog.

Question 11.
The big dog is also ___ the fat dog.
Answer: The big dog is also next to the fat dog.

Draw.

Question 12.
an apple on the last plate from the right a banana on the plate next to the apple an orange on the sixth plate from the left

Answer:

Read the clues to answer the question. Then write the letters in the correct

Question 13.
What is the capital of the United States of America?

Clues:

a. second letter from the right

b. fourth letter from the left

c. fifth letter from the left

d. third letter from the left

e. seventh letter from the left

f. fourth letter from the right

g. first letter on the left

h. the letter next to “G”

j. last letter from the left

j. letter between “S” and “I”

Answer: Washington