Go through the Math in Focus Grade 5 Workbook Answer Key Chapter 3 Practice 6 Subtracting Mixed Numbers to finish your assignments.
Math in Focus Grade 5 Chapter 3 Practice 6 Answer Key Subtracting Mixed Numbers
Subtract. Express each difference in simplest form.
Example
Question 1.
Answer:
Explanation:
The difference is found between two mixed fractions
as the denominators are same we directly subtracted the fraction
Subtract. Express each difference ¡n simplest form.
Question 2.
Answer:
Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then subtracted.
Question 3.
3\(\frac{5}{9}\) – 1\(\frac{1}{2}\)
Answer:
Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then subtracted.
Question 4.
7\(\frac{5}{6}\) – 2\(\frac{1}{4}\)
Answer:
Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then subtracted.
Subtract. Express each difference as a mixed number.
Question 5.
Answer:
Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done
Subtract. Express each difference as a mixed number.
Question 6.
Answer:
Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done
Question 7.
4\(\frac{1}{5}\) – 1\(\frac{1}{3}\)
Answer:
Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done
Question 8.
6\(\frac{3}{8}\) – 3\(\frac{5}{6}\)
Answer:
Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done
Question 9.
7\(\frac{1}{4}\) – 5\(\frac{11}{12}\)
Answer:
Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done
Question 10.
8\(\frac{1}{3}\) – 4\(\frac{3}{4}\)
Answer:
Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done
Use benchmarks to estimate each difference.
Example
Question 11.
12\(\frac{2}{5}\) – 8\(\frac{7}{12}\)
Answer:
12\(\frac{2}{5}\) – 8\(\frac{7}{12}\) = 4
Explanation:
\(\frac{2}{5}\) is about \(\frac{1}{2}\)
so, 12\(\frac{2}{5}\) is about 12\(\frac{1}{2}\)
\(\frac{7}{12}\) is about \(\frac{1}{2}\)
so, 8\(\frac{7}{12}\) is about 8\(\frac{1}{2}\)
12\(\frac{1}{2}\) – 8\(\frac{1}{2}\) = 4
Question 12.
20\(\frac{1}{8}\) – 5\(\frac{3}{9}\)
Answer:
20\(\frac{1}{8}\) – 5\(\frac{3}{9}\) = 15
Explanation:
\(\frac{1}{8}\) is about 0
20 + 0 = 20
\(\frac{3}{9}\) is about 0
5 + 0 = 5
20 – 5 = 15