Go through the Math in Focus Grade 5 Workbook Answer Key Chapter 3 Practice 6 Subtracting Mixed Numbers to finish your assignments.

## Math in Focus Grade 5 Chapter 3 Practice 6 Answer Key Subtracting Mixed Numbers

**Subtract. Express each difference in simplest form.**

Example

Question 1.

Answer:

Explanation:

The difference is found between two mixed fractions

as the denominators are same we directly subtracted the fraction

**Subtract. Express each difference ¡n simplest form.**

Question 2.

Answer:

Explanation:

The difference is found between two mixed fractions

as the denominators are different we changed them to like denominators

then subtracted.

Question 3.

3\(\frac{5}{9}\) – 1\(\frac{1}{2}\)

Answer:

Explanation:

The difference is found between two mixed fractions

as the denominators are different we changed them to like denominators

then subtracted.

Question 4.

7\(\frac{5}{6}\) – 2\(\frac{1}{4}\)

Answer:

Explanation:

The difference is found between two mixed fractions

as the denominators are different we changed them to like denominators

then subtracted.

**Subtract. Express each difference as a mixed number.**

Question 5.

Answer:

Explanation:

The difference is found between two mixed fractions

as the denominators are different we changed them to like denominators

then we are unable to subtract the mixed fractions

so we converted the numerator as that difference can be done

**Subtract. Express each difference as a mixed number.**

Question 6.

Answer:

Explanation:

The difference is found between two mixed fractions

as the denominators are different we changed them to like denominators

then we are unable to subtract the mixed fractions

so we converted the numerator as that difference can be done

Question 7.

4\(\frac{1}{5}\) – 1\(\frac{1}{3}\)

Answer:

Explanation:

The difference is found between two mixed fractions

as the denominators are different we changed them to like denominators

then we are unable to subtract the mixed fractions

so we converted the numerator as that difference can be done

Question 8.

6\(\frac{3}{8}\) – 3\(\frac{5}{6}\)

Answer:

Explanation:

The difference is found between two mixed fractions

as the denominators are different we changed them to like denominators

then we are unable to subtract the mixed fractions

so we converted the numerator as that difference can be done

Question 9.

7\(\frac{1}{4}\) – 5\(\frac{11}{12}\)

Answer:

Explanation:

The difference is found between two mixed fractions

as the denominators are different we changed them to like denominators

then we are unable to subtract the mixed fractions

so we converted the numerator as that difference can be done

Question 10.

8\(\frac{1}{3}\) – 4\(\frac{3}{4}\)

Answer:

Explanation:

The difference is found between two mixed fractions

as the denominators are different we changed them to like denominators

then we are unable to subtract the mixed fractions

so we converted the numerator as that difference can be done

**Use benchmarks to estimate each difference.**

Example

Question 11.

12\(\frac{2}{5}\) – 8\(\frac{7}{12}\)

Answer:

12\(\frac{2}{5}\) – 8\(\frac{7}{12}\) = 4

Explanation:

\(\frac{2}{5}\) is about \(\frac{1}{2}\)

so, 12\(\frac{2}{5}\) is about 12\(\frac{1}{2}\)

\(\frac{7}{12}\) is about \(\frac{1}{2}\)

so, 8\(\frac{7}{12}\) is about 8\(\frac{1}{2}\)

12\(\frac{1}{2}\) – 8\(\frac{1}{2}\) = 4

Question 12.

20\(\frac{1}{8}\) – 5\(\frac{3}{9}\)

Answer:

20\(\frac{1}{8}\) – 5\(\frac{3}{9}\) = 15

Explanation:

\(\frac{1}{8}\) is about 0

20 + 0 = 20

\(\frac{3}{9}\) is about 0

5 + 0 = 5

20 – 5 = 15