Math in Focus Grade 4 Chapter 6 Practice 1 Answer Key Adding Fractions

Practice the problems of Math in Focus Grade 4 Workbook Answer Key Chapter 6 Practice 1 Adding Fractions to score better marks in the exam.

Math in Focus Grade 4 Chapter 6 Practice 1 Answer Key Adding Fractions

Find the equivalent fraction. Complete the model. Then add.

Example
Math in Focus Grade 4 Chapter 6 Practice 1 Answer Key Adding Fractions 1

Question 1.
Math in Focus Grade 4 Chapter 6 Practice 1 Answer Key Adding Fractions 2
Answer:
Math-in-Focus-Grade-4-Chapter-6-Practice-1-Answer-Key-Adding-Fractions-Find the equivalent fraction-1

Explanation:
\(\frac{2}{3}\) + \(\frac{2}{9}\)
= (6 + 2) ÷ 9
= 8 ÷ 9 or + \(\frac{8}{9}\)

 

Add. Write each answer in simplest form
Question 2.
Math in Focus Grade 4 Chapter 6 Practice 1 Answer Key Adding Fractions 3
Answer:
Math-in-Focus-Grade-4-Chapter-6-Practice-1-Answer-Key-Adding-Fractions-Find the equivalent fraction-2

Explanation:
\(\frac{3}{5}\) + \(\frac{3}{10}\)
= (6 + 3) ÷ 10
= 9 ÷ 10 or \(\frac{9}{10}\)

 

Question 3.
Math in Focus Grade 4 Chapter 6 Practice 1 Answer Key Adding Fractions 4
Answer:
Math-in-Focus-Grade-4-Chapter-6-Practice-1-Answer-Key-Adding-Fractions-Find the equivalent fraction-3

Explanation:
\(\frac{5}{12}\) + \(\frac{1}{3}\)
= (5 + 4) ÷ 12
= 9 ÷ 12
= 3 ÷ 4 or \(\frac{3}{4}\)

 

Question 4.
Find the sum of \(\frac{1}{6}\) and \(\frac{1}{12}\).
Answer:
\(\frac{1}{6}\) + \(\frac{1}{12}\)  = \(\frac{1}{4}\)

Explanation:
Sum:
\(\frac{1}{6}\) + \(\frac{1}{12}\)
= (2 + 1) ÷ 12
= 3 ÷ 12
= \(\frac{1}{4}\)

 

Question 5.
Add \(\frac{1}{4}\) to the answer in Exercise 4.
Answer:
\(\frac{1}{4}\) + \(\frac{1}{4}\)  = 1 ÷ 2 or \(\frac{1}{2}\)

Explanation:
Sum:
\(\frac{1}{4}\) + \(\frac{1}{4}\)
= (1 + 1) ÷ 4
= 2 ÷ 4
= 1 ÷ 2 or \(\frac{1}{2}\)

 

Question 6.
What is the sum of \(\frac{1}{8}\), \(\frac{1}{4}\) and \(\frac{3}{8}\)?
Answer:
\(\frac{1}{8}\) + \(\frac{1}{4}\) + \(\frac{3}{8}\) = 3 ÷ 4 or \(\frac{3}{4}\)

Explanation:
Sum:
\(\frac{1}{8}\) + \(\frac{1}{4}\) + \(\frac{3}{8}\)
= (1 + 2) ÷ 8 + \(\frac{3}{8}\)
= \(\frac{3}{8}\) + \(\frac{3}{8}\)
= (3 + 3) ÷ 8
= 6 ÷ 8
= 3 ÷ 4 or \(\frac{3}{4}\)

 

Question 7.
Add \(\frac{1}{3}\), \(\frac{3}{12}\) and \(\frac{5}{12}\)
Answer:
\(\frac{1}{3}\) + \(\frac{3}{12}\) + \(\frac{5}{12}\) = 1.

Explanation:
Sum:
\(\frac{1}{3}\) + \(\frac{3}{12}\) + \(\frac{5}{12}\)
= (4 + 3) ÷ 12 + \(\frac{5}{12}\)
= \(\frac{7}{12}\) + \(\frac{5}{12}\)
= (7 + 5) ÷ 12
= 12 ÷ 12
= 1.

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