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Practice the problems of Math in Focus Grade 3 Workbook Answer Key Chapter 10 Practice 3 Addition to score better marks in the exam.

Math in Focus Grade 3 Chapter 10 Practice 3 Answer Key Addition

Change dollars and cents to cents. Then add.

Example

Question 1.

Answer:

Explanation:
First we have to change dollars and cents to cents. We know that 1 us dollar is equal to 100 us cents.
Convert $14.70 into 1470¢ and $20.15 into 2015¢.
Add 1470¢ with 2015¢ the sum is 3485¢.
The cents 3485¢ in dollar form as $34.85.

Question 2.

Answer:

Explanation:
First we have to change dollars and cents to cents. We know that 1 us dollar is equal to 100 us cents.
Convert $65.05 into 6505¢ and $0.95 into 95¢.
Add 6505¢ with 95¢ the sum is 6600¢.
The cents 6600¢ in dollar form as $66.00.

Question 3.

Answer:

Explanation:
First we have to change dollars and cents to cents. We know that 1 us dollar is equal to 100 us cents.
Convert $20.70 into 2070¢ and $35.55 into 3555¢.
Add 2070¢ with 3555¢ the sum is 5625¢.
The cents 5625¢ in dollar form as $56.25.

Question 4.

Answer:

Explanation:
First we have to change dollars and cents to cents. We know that 1 us dollar is equal to 100 us cents.
Convert $3.65 into 365¢ and $32.75 into 3275¢.
Add 365¢ with 3275¢ the sum is 3640¢.
The cents 3640¢ in dollar form as $36.40.

Question 5.

Answer:

Explanation:
First we have to change dollars and cents to cents. We know that 1 us dollar is equal to 100 us cents.
Convert $4.65 into 465¢ and $73.25 into 7325¢.
Add 465¢ with 7325¢ the sum is 7790¢.
The cents 7790¢ in dollar form as $77.90.

Question 6.

Answer:

Explanation:
First we have to change dollars and cents to cents. We know that 1 us dollar is equal to 100 us cents.
Convert $93.20 into 9320¢ and $5.95 into 595¢.
Add 9320¢ with 595¢ the sum is 9915¢.
The cents 9915¢ in dollar form as $99.15.

Question 7.

Answer:

Explanation:
First we have to change dollars and cents to cents. We know that 1 us dollar is equal to 100 us cents.
Convert $15.85 into 1585¢ and $24.15 into 2415¢.
Add 1585¢ with 2415¢ the sum is 4000¢.
The cents 4000¢ in dollar form as $40.00.

Question 8.

Answer:

Explanation:
First we have to change dollars and cents to cents. We know that 1 us dollar is equal to 100 us cents.
Convert $25.25 into 2525¢ and $28.75 into 2875¢.
Add 2525¢ with 2875¢ the sum is 5400¢.
The cents 5400¢ in dollar form as $54.00.

Write the letter that matches each answer to find out.

Question 9.
How do you thank a person in Spanish?

Answer:

Look at the picture. Write the prices, and then add.

Example

Question 10.

Answer:

Explanation:
In the above image we can observe the price of the skateboard is $25.40. Here both are skate boards. Add $25.40 with $25.40 the sum is $50.80.

Question 11.

Answer:

Explanation:
In the above image we can observe the price of the radio is $80.65 and the price of the teddy bear is $18.75. Add $80.65 with $18.75 the sum is $99.40.

Question 12.

Answer:

Explanation:
In the above image we can observe the price of the hairdryer is $39.15 and the price of the toy car is $56.95. Add $39.15 with $56.95 the sum is $96.10.

Question 13.

Answer:

Explanation:
In the above image we can observe the price of the iron is $71.40 and the price of the teddy bear is $18.75. Add $71.40 with $18.75 the sum is $90.15.

Question 14.

Answer:

Explanation:
In the above image we can observe the price of the toy car is $56.95 and the price of the teddy bear is $18.75. Add $56.95 with $18.75 the sum is $75.70.

Go through the Math in Focus Grade 2 Workbook Answer Key Chapter 5 Practice 4 Real-World Problems: Multiplication and Division to finish your assignments.

Math in Focus Grade 2 Chapter 5 Practice 4 Answer Key Real-World Problems: Multiplication and Division

Solve.

Question 1.
There are 2 plates. Each plate has 5 strawberries. How many strawberries are there?
5 + 5 = ___
2 × 5 = ___
There are __ strawberries.

Answer:
Given that
There are 2 plates each plate as 5 strawberries.
To find the number of strawberries there are 2 possible ways they are
5 + 5 = 10
5 × 2 = 10
Therefore there are 10 strawberries.

Question 2.
There are 6 bags. Each bag has 3 pockets. How many pockets are there?

There are ___ pockets.
Answer:
Given that
Number of bags are 6.
Each bag as 3 pockets.
To find the number of pockets there are two possible ways they are
3 + 3 + 3 + 3 + 3 + 3 = 18
6 × 3 = 18
Therefore number of pockets are 18.

Question 3.
Tim has 4- jars. There are 6 marbles in each jar. How many marbles does Tim have altogether?

Tim has ___ marbles altogether.
Answer:
Given that
Number of jars near tim = 4
There are 6 marbles in each jar.
Number of marbles = 6 × 4 = 24.
Tim has 24 marbles altogether.

Question 4.
Yanthi has 5 boxes. There are 8 pencils in each box. How many pencils does she have altogether?

Yanthi has ___ pencils altogether.
Answer:
Given that
Yanthi has 5 boxes.
There are 8 pencils in each box.
Number of pencils = 8 × 5 = 40
Yanthi has 40 pencils altogether.

Question 5.

Aunt Emma has 3 nephews. She buys 9 kites. She gives each nephew an equal number of kites. How many kites does each nephew get?
____ – ___ – ___ – ___ = 0
______ ÷ ___ = ____
Each nephew gets __ kites.
Answer:
Given that
The Aunt Emma has 3 nephews
She buys 9 kites.
She gives each nephew an equal number of kites.
9 – 3 – 3 – 3 = 0
9 ÷ 3 = 3
Each nephew gets 3 kites.

Question 6.

Mr. O’Brien catches 28 fish. He puts 7 fish in each bucket. How many buckets does he have?
____ – ___ – ___ – ___ = 0
______ ÷ ___ = ____
He has __ buckets.
Answer:
Given that
Mr. O’Brien catches 28 fishes.
She puts 7 fishes in each bucket.
Number of buckets are
28 – 7 – 7 – 7 – 7 = 0
28 ÷ 7 = 4
Therefore he has 4 buckets.

Practice the problems of Math in Focus Grade 6 Workbook Answer Key Chapter 8 Equations and Inequalities to score better marks in the exam.

Math in Focus Grade 6 Course 1 B Chapter 8 Answer Key Multiplying and Dividing Fractions and Decimals

Math in Focus Grade 6 Chapter 8 Quick Check Answer Key

Complete with =, >, or <.

Question 1.
25 -26
Answer:
25 > -26,

Explanation:
Given to compare 25 and -26 as 25 is greater than -26 therefore 25 > -26.

Question 2.
12 + 12 + 12 3 ∙ 12
Answer:
12 + 12 + 12 = 36,

Explanation:
As 12 + 12 + 12 = 36 and 3 X 12 is 36 so both are equal therefore 12  + 12 + 12 = 36.

Question 3.
40 ÷ 8 8 ÷ 40
Answer:
40 ÷ 8 = 8 ÷ 40,

Explanation:
As 40 ÷ 8 is 5 and 8 ÷ 40 is 5 therefore 40 ÷ 8 = 8 ÷ 40.

Question 4.
-16 -7
Answer:
-16 < -7,

Explanation:
Given to compare between – 16 and – 7 as – 16 is lessthan -7 so -16 < -7.

Write an algebraic expression for each of the following.

Question 5.
The sum of 15 and p
Answer:
x = 15 + p,

Explanation:
An algebraic expression for the sum of 15 and p, let it be x so x = 15 + p.

Question 6.
The difference “q less than 10”
Answer:
x – q < 10,

Explanation:
Given the difference “q less than 10” is let it be x so  x – q < 10.

Question 7.
The product of r and 23
Answer:
x = r X 23,

Explanation:
Given the product of r and 23 is let it be x so x = r X 23.

Question 8.
Divide s by 11.
Answer:
x = s ÷ 11,

Explanation:
Given divide s by 11 so let it be x so x = s ÷ 11.

Evaluate each expression for the given values of the variable.

Question 9.
3x + 5 when x = 9 and x = 12
Answer:
3x + 5 = 32, when x = 9,
3x + 5 = 41, when x = 12,

Explanation:
Given to find 3x + 5 when x = 9, so 3 X 9 + 5 = 27 + 5 = 32, when x = 12 we get 3x + 5 = 3 x 12 + 5 = 36 + 5 = 41.

Question 10.
28 – 4x when x = 4 and x = 7
Answer:
28 – 4x = 12, when x = 4,
28 – 4x = 0 when x = 7,

Explanation:
Given when x = 4 the equation 28 – 4x is 28 – 16 = 12, when x = 7 then the equation becomes 28 – 4 X 7 = 28 – 28 = 0.

Plot the points on a coordinate plane.

Question 11.
K (2, 1), L (3, 3), M (0, 6), and N (7, 5)
Answer:

Explanation:
Given to plot the points on a coordinate plane as K (2, 1), L (3, 3), M (0, 6), and N (7, 5) above.

This handy Math in Focus Grade 3 Workbook Answer Key Chapter 19 Practice 3 Square Units (m² and ft²) detailed solutions for the textbook questions.

Math in Focus Grade 3 Chapter 19 Practice 3 Answer Key Square Units (m² and ft²)

Find the area of each shaded figure in square meters. Then complete the table.

Question 1.

Answer:

Explanation:
The simplest (and most commonly used) area calculations are for squares and rectangles.
To find the area of a rectangle, multiply its height by its width.
For a square you only need to find the length of one of the sides (as each side is the same length) and,
then multiply this by itself to find the area.

Question 2.
Which figure has the smallest area? Figure ____________
Answer:
Figure A
Explanation:
Compare all the figures given in the grid,
figure A has smallest area 4 square meters.

Question 3.
Which figure has the largest area? Figure ____________
Answer:
Figure D
Explanation:
Compare all the figures given in the grid,
figure D has greatest area 9 square meters.

Question 4.
Which figures have the same area? Figures ____________
Answer:
Figure B & Figure C
Explanation:
Compare all the figures given in the grid,
figure A and B has the same area 6 square meters.

Find the area of each shaded figure in square feet. Then complete the table.

Question 5.

Answer:

Explanation:
The simplest (and most commonly used) area calculations are for squares and rectangles.
To find the area of a rectangle, multiply its height by its width.
For a square you only need to find the length of one of the sides (as each side is the same length) and,
then multiply this by itself to find the area.

Question 6.
Which figure has the largest area? Figure ____________
Answer:
Figure D
Explanation:
Compare all the figures given in the grid,
figure D has largest area 13 square feet.

Question 7.
Which figure has the smallest area? Figure _____________
Answer:
Figure A
Explanation:
Compare all the figures given in the grid,
figure A has smallest area 3 square feet.

The figures are made of square and half-square tiles. Find the area of each shaded figure. Then complete the table.

Question 8.

Answer:

Explanation:
The simplest (and most commonly used) area calculations are for squares and rectangles.
To find the area of a rectangle, multiply its height by its width.
For a square you only need to find the length of one of the sides (as each side is the same length) and,
then multiply this by itself to find the area.

Make square pieces of paper with an area of 1 square meter and 1 square foot. Use a ruler and scissors to cut out the squares.

Estimate the area in square feet.

Question 9.
Your kitchen floor
About _________ m².
Answer: 80 m²
Explanation:
Measurements may vary from one to one,
depending upon the size of the kitchen.
So, we use the square meter to estimate the area of the kitchen.
Question 10.
Your bed
About ____________ ft².
Answer: 200 ft²
Explanation:
Measurements may vary from one to one,
depending upon the size of the bed.
So, we use the square feet to estimate the area of the bed.

Use the square meter and square foot paper to estimate the area of these objects in your house.

Question 11.

Answer:

Explanation:
Measurements may vary from one to one,
depending upon the size, shape of the objects.
So, we use the square meter and square foot paper to estimate the area of these objects in our house.

Go through the Math in Focus Grade 5 Workbook Answer Key Chapter 3 Practice 6 Subtracting Mixed Numbers to finish your assignments.

Math in Focus Grade 5 Chapter 3 Practice 6 Answer Key Subtracting Mixed Numbers

Subtract. Express each difference in simplest form.

Example

Question 1.

Answer:

Explanation:
The difference is found between two mixed fractions
as the denominators are same we directly subtracted the fraction

Subtract. Express each difference ¡n simplest form.

Question 2.

Answer:

Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then subtracted.

Question 3.
3\(\frac{5}{9}\) – 1\(\frac{1}{2}\)
Answer:

Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then subtracted.

Question 4.
7\(\frac{5}{6}\) – 2\(\frac{1}{4}\)
Answer:

Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then subtracted.

Subtract. Express each difference as a mixed number.

Question 5.

Answer:

Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done

Subtract. Express each difference as a mixed number.

Question 6.

Answer:

Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done

Question 7.
4\(\frac{1}{5}\) – 1\(\frac{1}{3}\)
Answer:

Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done

Question 8.
6\(\frac{3}{8}\) – 3\(\frac{5}{6}\)
Answer:

Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done

Question 9.
7\(\frac{1}{4}\) – 5\(\frac{11}{12}\)
Answer:

Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done

Question 10.
8\(\frac{1}{3}\) – 4\(\frac{3}{4}\)
Answer:

Explanation:
The difference is found between two mixed fractions
as the denominators are different we changed them to like denominators
then we are unable to subtract the mixed fractions
so we converted the numerator as that difference can be done

Use benchmarks to estimate each difference.

Example

Question 11.
12\(\frac{2}{5}\) – 8\(\frac{7}{12}\)
Answer:
12\(\frac{2}{5}\) – 8\(\frac{7}{12}\) = 4
Explanation:
\(\frac{2}{5}\) is about \(\frac{1}{2}\)
so, 12\(\frac{2}{5}\)  is about 12\(\frac{1}{2}\)
\(\frac{7}{12}\) is about \(\frac{1}{2}\)
so, 8\(\frac{7}{12}\)  is about 8\(\frac{1}{2}\)
12\(\frac{1}{2}\) – 8\(\frac{1}{2}\) = 4

Question 12.
20\(\frac{1}{8}\) – 5\(\frac{3}{9}\)
Answer:
20\(\frac{1}{8}\) – 5\(\frac{3}{9}\) = 15
Explanation:
\(\frac{1}{8}\) is about 0
20 + 0 = 20
\(\frac{3}{9}\) is about 0
5 + 0 = 5
20 – 5 = 15

Go through the Math in Focus Grade 5 Workbook Answer Key Chapter 4 Practice 7 Real-World Problems: Multiplying and Dividing with Fractions to finish your assignments.

Math in Focus Grade 5 Chapter 4 Practice 7 Answer Key Real-World Problems: Multiplying and Dividing with Fractions

Solve. Draw models to help you.

Question 1.
Evan typed 72 pages of notes one day. He typed \(\frac{1}{2}\) of the pages in the morning and \(\frac{1}{3}\) of the pages in the afternoon. He typed the rest of the pages in the evening. How many pages of notes did he type in the morning and afternoon?
Answer:
48 pages of notes that he typed in the morning and afternoon
24 pages he typed in the evening.
Explanation:
Evan typed 72 pages of notes one day.
\(\frac{1}{2}\) of the pages in the morning  72 ÷ 2 = 36
\(\frac{1}{3}\) of the pages in the afternoon 36 ÷  3 = 12
36 + 12 = 48
He typed the rest of the pages in the evening. 72 – 48 = 24

Question 2.
Last Saturday, Jay spent 6 hours playing games, studying and talking with his friends. He spent \(\frac{2}{5}\) of the time playing games and \(\frac{1}{2}\) of the time studying. How many minutes did he spend talking with his friends?
Answer:
36 minutes
Explanation:
To find \(\frac{2}{5}\) of the time, all you have to do is multiply is by the time!!!
\(\frac{2}{5}\)   x 360 = 144 minutes
6 x 60 = 360
1 hour has 60 minutes.
Studying:
\(\frac{1}{2}\) x 360 = 180 minutes

Talking with friends = Total time – playing games – studying
360 – 144 – 180 = 36 minutes

Solve. Draw models to help you.

Question 3.
Joanne earns $720 a week. She spends \(\frac{1}{3}\) of her money on groceries and household goods and \(\frac{3}{4}\) of the remaining money on rent. How much money does she spend on rent, groceries and household goods?
Answer:
$600
Explanation:
720 x \(\frac{1}{3}\) = 240 for Groceries and home goods.
then 720 – 240 = 480 reaming
then 480 x  \(\frac{3}{4}\) = 360 for rent
total amount spent= 240 + 360 = 600 dollar total

Solve. Draw models to help you.

Question 4.
During a triathlon, Sharon swims \(\frac{1}{4}\) of the total route and cycles \(\frac{3}{5}\) of the remaining route. She runs the rest of the route. If she runs 3,600 meters, find the total distance of the triathlon route.
Answer:
6km swimming, 14.4km cycling and 3.6km running

Solve. Show your work.

Question 5.
Victoria has a 2-pound package of flour. She uses \(\frac{2}{5}\) of the flour to make a pizza. She then uses \(\frac{3}{10}\) of the remaining flour to make bread. Find the weight of the package of flour that she has left. Express your answer as a decimal.
Answer:
\(\frac{9}{25}\) lb. left = 0.36 in decimal.
Explanation:
Victoria has a 2-pound package of flour.
\(\frac{2}{5}\) of the flour to make a pizza.  \(\frac{3}{5}\) x 2 = \(\frac{6}{5}\)lb.
She then uses \(\frac{3}{10}\) of the remaining flour to make bread \(\frac{3}{10}\) x \(\frac{6}{5}\)
= \(\frac{18}{50}\) = \(\frac{9}{25}\) lb. left = 0.36

Solve. Show your work.

Question 6.
Karen collects \(\frac{6}{7}\) quart of rainwater. She uses \(\frac{1}{2}\) of the water to clean her bicycle and uses the remaining water equally for 3 houseplants. What volume of water does she use for each houseplant?
Answer:
\(\frac{1}{9}\) quart volume of water that she use for each houseplant
Explanation:
Karen collects \(\frac{6}{7}\) quart of rainwater.
\(\frac{1}{2}\) of the water to clean her bicycle ( \(\frac{1}{2}\) ) x (\(\frac{6}{7}\)) = \(\frac{6}{14}\)= \(\frac{3}{7}\) quart
\(\frac{3}{7}\) x ( \(\frac{1}{3}\) ) = \(\frac{3}{21}\) = \(\frac{1}{9}\) quart

Question 7.
Ricardo spends \(\frac{8}{9}\) hour reading the newspaper. He spends \(\frac{1}{4}\) of the time reading the world news and splits the remaining time equally between the sports news and the comics. How much time does he spend reading the comics?
Answer:
\(\frac{1}{3}\)  time that he spend reading the comics
Explanation:
Ricardo spends \(\frac{8}{9}\) hour reading the newspaper.
latex]\frac{1}{4}[/latex] x \(\frac{8}{9}\) = \(\frac{24}{36}\) =  \(\frac{2}{3}\) hour
He spends \(\frac{1}{4}\) of the time reading the world news and splits the remaining time equally between the sports news and the comics.
\(\frac{2}{3}\) x \(\frac{1}{2}\) – \(\frac{2}{6}\) = \(\frac{1}{3}\) hour reading comics

Solve. Show your work

Question 8.
A square foot of wall space needs \(\frac{1}{8}\) quart of paint. Terrence has 7 quarts of paint, but uses 2 quarts to paint a pipe. How many square feet of wall can he paint with the rest of the paint?
Answer:
40 square feet of wall that he can he paint with the rest of the paint
Explanation:
Terrence has 7 quarts of paint, but uses 2 quarts to paint a pipe.
7 – 2 = 5
fifths of ( \(\frac{1}{8}\) )
5 x 8 = 40 square feet

Question 9.
Mary spends \(\frac{1}{6}\) hour to make a friendship bracelet. She spends 3 hours before lunch and 2 hours after lunch making the bracelets. How many bracelets does she make in all?
Answer:
30 bracelets that she make in all
Explanation:
1 hour = 60 minutes
Mary spends \(\frac{1}{6}\) hour to make a friendship bracelet.
60 ÷ 6 = 10
She spends 3 hours before lunch and 2 hours after lunch making the bracelets.
3 + 2 = 5
5 x 60 = 300
300  ÷  10 = 30

Question 10.
Clayton wants to be a musician. After school one afternoon, he spends half his time practicing his drums and \(\frac{3}{4}\) of the remaining time on homework and dinner. He spends the remaining \(\frac{3}{4}\) hour talking with and texting his friends. How long did he practice the drums?
Answer:

Explanation:

Question 11.
Julia spends \(\frac{5}{9}\) of her vacation at summer camp. She spends \(\frac{3}{4}\) of the remaining time at her grandparent’s home. The remaining 7 days she spends at the seashore with her family. How many days of summer vacation does she get each summer.
Answer:
Explanation:

Go through the Math in Focus Grade 2 Workbook Answer Key Chapter 3 Practice 8 Subtraction with Regrouping in Hundreds, Tens, and Ones to finish your assignments.

Math in Focus Grade 2 Chapter 3 Practice 8 Answer Key Subtraction with Regrouping in Hundreds, Tens, and Ones

Solve.

Show how to check your answer.

Question 1.
817 children will march in the Thanksgiving Day Parade. 359 of the children are girls. How many are boys?
____ are boys.
Answer:
458 boys.

Explanation:
Given that 817 children will march in the Thanksgiving Day Parade and 359 of the children are girls. So the number of boys is 817-359 which is 458 boys.

Question 2.
There are 605 children at a swimming pool. There are 278 girls. How many are boys?
___ are boys.
Answer:
327 are boys.

Explanation:
Given that there are 605 children at a swimming pool and there are 278 girls. So the number of boys are 605-278 which is 327 boys.

Question 3.
A sandwich shop sells 456 ham sandwiches. It sells 298 fewer cheese sandwiches than ham sandwiches. How many cheese sandwiches does it sell?

It sells ____ cheese sandwiches.
Answer:
It sells 158 cheese sandwiches.

Explanation:
Given that a sandwich shop sells 456 ham sandwiches and it sells 298 fewer cheese sandwiches than ham sandwiches. So the number of cheese sandwiches is 456-298 which is 158 cheese sandwiches.

Solve.

Show how to check your answer.

Question 4.
Hal drove 853 miles this year on his vacation. This was 154- more miles than he drove last year. How many miles did Hal drive on vacation last year?
Hal drove ___ miles on vacation last year.
Answer:
Hal drove 1,007 miles on vacation last year.

Explanation:
Given that Hal drove 853 miles this year on his vacation and this was 154 more miles than he drove last year. So the number of miles did Hal drive on vacation last year is 853+154 which is 1,007 miles. So Hal drove 1,007 miles on vacation last year.

Question 5.
Mrs. Ruiz makes 381 glasses of apple juice for a school fair. She sells 192 glasses. How many glasses of apple juice does Mrs. Ruiz have left?
Mrs. Ruiz has ___ glasses of apple juice left.
Answer:
Mrs. Ruiz has 189 glasses of apple juice left.

Explanation:
Given that Mrs. Ruiz makes 381 glasses of apple juice for a school fair and she sells 192 glasses. So the number of glasses of apple juice does Mrs. Ruiz has left is 381-192 which is 189 glasses.

Question 6.
Tracey has 982 stickers. She has 496 stickers more than Zach. How many stickers does Zach have? zach has ___ stickers.
Answer:
Zach has 1,478 stickers.

Explanation:
Given that Tracey has 982 stickers and she has 496 stickers more than Zach. So the number of stickers does Zach had is 982+496 which is 1,478 stickers.

Go through the Math in Focus Grade 4 Workbook Answer Key Chapter 5 Practice 2 Median, Mode, and Range to finish your assignments.

Math in Focus Grade 4 Chapter 5 Practice 2 Answer Key Median, Mode, and Range

Find the median, mode, and range.

Example
4, 6, 5, 6, 8, 8, 10, 8
Find the median.

Arrange the numbers in order from least to greatest. The middle number or the mean of the two middle numbers is the median.

Since there are two middle numbers, 6 and 8, find the mean of the two numbers.
The median of the data set is \(\frac{6+8}{2}\) = \(\frac{14}{2}\) = 7
Find the mode.

The number that appears most often is the mode. There can be more than one mode, If all the numbers appear the same number of times, there is no mode.

Find the range.
4, 5, 6, 6, 8, 8, 8, 10
Range = 10 – 4
= 6
The range of the data set is 6.
The difference between the greatest and the least number is the range.

Find the median, mode, and range of each set of data.

Question 1.
50, 52, 58, 50, 47, 43, 52, 60, 49, 52
Median:
Mode:
Range:

Answer:
Median: 51
Mode: 52
Range: 17.

Explanation:
Given the data set is 50, 52, 58, 50, 47, 43, 52, 60, 49, 52. So to find the median we will arrange the numbers in order from least to greatest. The middle number or the mean of the two middle numbers is the median. So the numbers in order from least to greatest are 43,47,49,50,50,52,52,52,58,60. The middle numbers are 50 and 52, so the median is
Median = \(\frac{50+52}{2}\)
= \(\frac{102}{2}\)
= 51.
To find the mode we will pick the number that appears most often is the mode and there can be more than one mode, If all the numbers appear the same number of times, there is no mode. So here the mode will be 52.
To find the range, we will find the difference between the greatest and the least number.
So the range is 60-43 which is 17.

Question 2.
15 in., 18 in., 12 in., 14 in., 30 in., 15 in., 15 in.
Median:
Mode:
Range:

Answer:
Median: 15 in.
Mode: 15 in.
Range: 18 in.

Explanation:
Given the data set is 15 in., 18 in., 12 in., 14 in., 30 in., 15 in., 15 in.. So to find the median we will arrange the numbers in order from least to greatest. The middle number or the mean of the two middle numbers is the median. So the numbers in order from least to greatest are 12 in., 14 in., 15 in.,15 in.,15 in.,18 in.,30 in. The middle numbers are 50 and 52, so the median is
Median = 15 in.
To find the mode we will pick the number that appears most often is the mode and there can be more than one mode, If all the numbers appear the same number of times, there is no mode. So here the mode will be 15.
To find the range, we will find the difference between the greatest and the least number.
So the range is 30-12 which is 18 in.

Question 3.
9 lb, 11lb, 14 lb, 20 lb, 14 lb, 20 lb, 14 lb, 20 lb
Median:
Mode:
Range:

Answer:
Median: 15 in.
Mode: 15 in.
Range: 18 in.

Explanation:
Given the data set is 9 lb, 11lb, 14 lb, 20 lb, 14 lb, 20 lb, 14 lb, 20 lb. So to find the median we will arrange the numbers in order from least to greatest. The middle number or the mean of the two middle numbers is the median. So the numbers in order from least to greatest are 12 in., 14 in., 15 in.,15 in.,15 in.,18 in.,30 in. The middle numbers are 50 and 52, so the median is
Median = 15 in.
To find the mode we will pick the number that appears most often is the mode and there can be more than one mode, If all the numbers appear the same number of times, there is no mode. So here the mode will be 15.
To find the range, we will find the difference between the greatest and the least number.
So the range is 30-12 which is 18 in.

Example
The line plot shows the number of words spelled correctly by each contestant in a spelling bee. Each ✗represents one contestant.

Number of Words Spelled Correctly
An ✗ above 15 on the number line represents a contestant who spelled 15 words correctly.

Complete. Use the data in the line plot.

____ contestants took part in the spelling bee.
The median number of words spelled correctly is 14
The number of contestants who spelled the greatest number of words correctly is 4
The mode of the set of data is 15 words.
The difference between the greatest and the least number of words spelled correctly is 5

Answer:
11 contestants took part in the spelling bee.

Explanation:
Here, 11 contestants took part in the spelling bee.
The data will be 10,11,12,12,13,14,14,15,15,15,15.

Make a line plot to show the data.

The table shows the number of bull’s eyes each player scored out of 10 shots in a dart competition.

Complete. Use the data in your line plot.

Question 4.
The median number of bull’s eyes scored is ____
Answer:
The median number of bull’s eyes scored is 1.5.

Explanation:
The median number of bull’s eyes scored is, here we will arrange the numbers in order from least to greatest. The middle number or the mean of the two middle numbers is the median. So the numbers in order from least to greatest are 0,1,1,2,3,4. The median number is
= \(\frac{1+2}{2}\)
= \(\frac{3}{2}\)
= 1.5.

Question 5.
There are ___ players altogether.
Answer:
There are 11 players.

Explanation:
The number of players are 0+1+1+2+3+4 which is 11 players.

Question 6.
The number of bull’s eyes that was scored the most is ___
Answer:
The number of bull’s eyes that was scored the most is 8.

Question 7.
The range of the set of data is ___
Answer:
The range of the set of data is 4.

Explanation:
To find the range, we will find the difference between the greatest and the least number.
So the range is 4-0 which is 4.

Question 8.
____ players scored 7 bull’s eyes, and the winner scored
___ bull’s eyes.
Answer:
3 players scored 7 bull’s eyes, and the winner scored 4 bull’s eyes.

Complete the table based on the information given.

A number cube has six faces numbered 1 to 6. John tossed two number cubes several times and added the numbers each time.

Complete. Use the data in the table.

Question 9.
John threw the two number cubes ____ times altogether.
Answer:

Question 10.
Make a line plot to show the total for each toss.
Answer:

Question 11.
The median of the set of data is _____
Answer:

Question 12.
The mode of the set of data is ______
Answer:

Question 13.
The range of the set of data is ____
Answer:

Find the mean of each set of data.

Example
Haley made a line plot to show the number of points she scored in a computer math game over three weeks.

20 points × 2 times = 40
30 points × 4 times = 120
40 points × 2 times = 80

Haley’s mean score for each game in Week 1 is 30 points.

Question 14.

15 points × ____ time(s) = ___
20 points × ____ time(s) = ___
25 points × ____ time(s) = ___
30 points × ____ time(s) = ___
35 points × ____ time(s) = ___
Mean = ___
= ____ = _____
Haley’s mean score for each game in Week 2 is ___ points.

Answer:
Haley’s mean score for each game in Week 2 is 25 points.

Explanation:
Haley’s mean score for each game in Week 2 is  1,3,1,1,2
15 points × 1 time(s) = 15
20 points × 3 time(s) = 60
25 points × 1 time(s) = 25
30 points × 1 time(s) = 30
35 points × 2 time(s) = 70
Here, the mean is 25.
Haley’s mean score for each game in Week 2 is 25 points.

Find the mean of the set of data.

Question 15.

20 points × ____ time(s) = ___
25 points × ____ time(s) = ___
30 points × ____ time(s) = ___
35 points × ____ time(s) = ___
40 points × ____ time(s) = ___
Mean = ___
= ____ = _____
Haley’s mean score for each game in Week 3 is ___ points.
Answer:
Haley’s mean score for each game in Week 3 is 60 points.

Explanation:
20 points × 2 time(s) = 40
25 points × 1 time(s) = 25
30 points × 3 time(s) = 60
35 points × 1 time(s) = 35
40 points × 2 time(s) = 80
Haley’s mean score for each game in Week 3 is 60 points.

Question 16.
Compare the line plots for Weeks 2 and 3. Can you tell which data set has a greater mean just by looking at the line plots? What part of the line plot makes you think that?
Answer:
Week 3 has a greater mean.

Explanation:
The mean for week 2 is 25 points and the mean for week 3 is 60 points. So week 3 has a greater mean.

Practice the problems of Math in Focus Grade 4 Workbook Answer Key Chapter 6 Practice 8 Real-World Problems: Fractions to score better marks in the exam.

Math in Focus Grade 4 Chapter 6 Practice 8 Answer Key Real-World Problems: Fractions

Solve. Show your work.

Example
Ali bought three pockets of dried fruit.

What is the total weight of all three packets of dried fruit?

The total weight of aB three packets of dried fruit is \(\frac{5}{6}\) pound.

Solve. Show your work.

Question 1.
Jim had three waffles.
He ate \(\frac{1}{6}\) of one waffle, and \(\frac{2}{3}\) of another waffle.
How many waffles were left?
Answer:
Amount of waffles were left = 13 ÷ 6 or \(\frac{13}{6}\)

Explanation:
Amount of waffles he ate = \(\frac{1}{6}\) of one waffle + \(\frac{2}{3}\) of another waffle.
Amount of waffles were left = (1 – \(\frac{1}{6}\) ) + (1 – \(\frac{2}{3}\)) + 1
= [(6-1) ÷ 6] + [(3-2) ÷ 3] + 1
= \(\frac{5}{6}\) + \(\frac{1}{3}\) + 1
= [(5 + 2) ÷ 6] + 1
= \(\frac{7}{6}\) + 1
= (7 + 6) ÷ 6
= 13 ÷ 6 or \(\frac{13}{6}\)

Question 2.
A grocery store has 5 pounds of granola. One customer buys \(\frac{2}{3}\) pound of granola and another buys \(\frac{5}{6}\) pound. After these purchases, how much granola is left?
Answer:
Number of pounds left over = 5 ÷ 3 or  \(\frac{5}{3}\)

Explanation:
Number of pounds one customer buys = \(\frac{2}{3}\)  of granola
=> \(\frac{2}{3}\) × 5
=> \(\frac{10}{3}\)
Number of pounds another customer buys = \(\frac{5}{6}\)
Total number of pounds granola grocery store has = 5.
Total number of pounds granola grocery store has = Number of pounds one customer buys + Number of pounds another customer buys + Number of pounds left over
=> 5 = \(\frac{10}{3}\) + \(\frac{5}{6}\) + Number of pounds left over
=> 5 = [(20 + 5) ÷ 6] + Number of pounds left over
=> 5 = \(\frac{10}{3}\) + Number of pounds left over
=> 5 – \(\frac{10}{3}\)  = Number of pounds left over
=> (15 – 10) ÷ 3 = Number of pounds left over
=> \(\frac{5}{3}\)  or 5 ÷ 3 = Number of pounds left over

Question 3.
Karen jogs \(\frac{1}{2}\) mile. Selma jogs \(\frac{1}{4}\) mile more than Karen. Lena jogs \(\frac{3}{4}\) mile more than Selma. How far does Lena jog?
Answer:
Number of miles Lena jogs = \(\frac{3}{2}\)

Explanation:
Number of miles Karen jogs = \(\frac{1}{2}\)
Selma jogs \(\frac{1}{4}\) mile more than Karen.
=> Number of miles Selma jogs = Number of miles Karen jogs + \(\frac{1}{4}\)
= \(\frac{1}{2}\) + \(\frac{1}{4}\)
= (2 + 1) ÷ 4
= \(\frac{3}{4}\)
Lena jogs \(\frac{3}{4}\) mile more than Selma.
=> Number of miles Lena jogs = Number of miles Selma jogs + \(\frac{3}{4}\)
= \(\frac{3}{4}\) + \(\frac{3}{4}\)
= \(\frac{6}{4}\)
= \(\frac{3}{2}\)

Question 4.
Jeremy has 18 marbles. He loses 6 of them.

a. What fraction of the marbles does he lose?
Answer:
Fraction of the marbles he lost = 1 ÷ 3 or \(\frac{1}{3}\) or 0.33.

Explanation:
Total number of marbles Jeremy has = 18.
Number of marbles he loses = 6.
Fraction of the marbles he lost = Number of marbles he loses ÷ Total number of marbles Jeremy has
= 6 ÷ 18
= 1 ÷ 3 or \(\frac{1}{3}\) or 0.33.

b. What fraction of the marbles does he have left?
Answer:
Fraction of the marbles does he have left = 2 ÷ 3 or \(\frac{2}{3}\) or 0.67.

Explanation:
Total number of marbles Jeremy has = 18.
Number of marbles he loses = 6.
Number of the marbles he have left = Total number of marbles Jeremy has – Number of marbles he loses
= 18 – 6
= 12.
Fraction of the marbles does he have left = Number of the marbles he have left ÷ Total number of marbles Jeremy has
= 12 ÷ 18
= 2 ÷ 3 or \(\frac{2}{3}\) or 0.67.

Question 5.
Mrs. Yan buys 4 red tulips and 5 yellow tulips.

a. What fraction of the tulips are red?
Answer:
Fraction of the tulips are red = 4 ÷ 9 or \(\frac{4}{9}\)

Explanation:
Number of red tulips Mrs. Yan buys = 4.
Number of yellow tulips Mrs. Yan buys = 5.
Total number of tulips Mrs. Yan buys = Number of red tulips Mrs. Yan buys + Number of yellow tulips Mrs. Yan buys
= 4 + 5
= 9.
Fraction of the tulips are red = Number of red tulips Mrs. Yan buys ÷ Total number of tulips Mrs. Yan buys
= 4 ÷ 9 or \(\frac{4}{9}\)

b. What fraction of the tulips are yellow?
Answer:
Fraction of the tulips are yellow = 5 ÷ 9 or \(\frac{5}{9}\)

Explanation:
Number of red tulips Mrs. Yan buys = 4.
Number of yellow tulips Mrs. Yan buys = 5.
Total number of tulips Mrs. Yan buys = Number of red tulips Mrs. Yan buys + Number of yellow tulips Mrs. Yan buys
= 4 + 5
= 9.
Fraction of the tulips are yellow = Number of yellow tulips Mrs. Yan buys ÷ Total number of tulips Mrs. Yan buys
= 5 ÷ 9 or \(\frac{5}{9}\)

Question 6.
Charles owns 3 cats, 4 goldfish, and some parakeets. Altogether, he has 10 pets.

a. What fraction of his pets are goldfish?
Answer:
Fraction of his pets are goldfish = 2 ÷ 5 or \(\frac{2}{5}\)

Explanation:
Number of cats Charles owns = 3.
Number of goldfish Charles owns = 4.
Total number of pets Charles owns = 10.
Fraction of his pets are goldfish = Number of goldfish Charles owns ÷ Total number of pets Charles owns
= 4 ÷ 10
= 2 ÷ 5 or \(\frac{2}{5}\)

b. What fraction of his pets are parakeets?
Answer:
Fraction of his pets are parakeets = 3 ÷ 10 or \(\frac{3}{10}\)

Explanation:
Number of cats Charles owns = 3.
Number of goldfish Charles owns = 4.
Total number of pets Charles owns = 10.
=> Total number of pets Charles owns  = Number of parakeets Charles owns + Number of cats Charles owns + Number of goldfish Charles owns
=> 10 = ?? + 3 + 4
=> 10 = ?? + 7
=> 10 – 7 = ??
=> 3 = ??.
Fraction of his pets are parakeets = Number of parakeets Charles owns ÷ Total number of pets Charles owns
= 3 ÷ 10 or \(\frac{3}{10}\)

Question 7.
Rick had $20. He spent $10 on food, $6 on a movie ticket and saved the rest.

a. How much money did he save?
Answer:
Amount of money he saved = $4.

Explanation:
Total amount of money Rick had = $20.
Amount of money Rick had spent on food = $10.
Amount of money Rick had spent on a movie ticket = $6.
Amount of money he saved = Total amount of money Rick had – (Amount of money Rick had spent on food + Amount of money Rick had spent on a movie ticket)
= $20 – ($10 + $6)
= $20 – $16
= $4.

b. What fraction of the total amount did he save?
Answer:
Fraction of the total amount did he save = 1 ÷ 5 or \(\frac{1}{5}\)

Explanation:
Total amount of money Rick had = $20.
Amount of money he saved = $4.
Fraction of the total amount did he save = Amount of money he saved ÷ Total amount of money Rick had
= 4 ÷ 20
= 1 ÷ 5 or \(\frac{1}{5}\)

Question 8.
There are 24 students in a class, and \(\frac{2}{3}\) of the students in the class are boys. How many students are girls?
Answer:
Number of girls in the class = 8.

Explanation:
Total number of students in the class = 24.
\(\frac{2}{3}\) of the students in the class are boys.
=> Number of boys in the class = Number of students in the class × \(\frac{2}{3}\)
= 24 × \(\frac{2}{3}\)
= 8 × 2
= 16.
Number of girls in the class = Total number of students in the class – Number of boys in the class
= 24 – 16
= 8.

Question 9.
One morning, The Shirt Shop sold 15 T-shirts.
Of the T-shirts sold, \(\frac{1}{5}\) were gray. The rest were white. How many white T-shirts were sold?
Answer:
Number of white T-shirts were sold = 12.

Explanation:
Number of T-shirts The Shirt Shop sold One morning = 15.
Of the T-shirts sold, \(\frac{1}{5}\) were gray.
=> Number of gray T-shirts sold = Number of T-shirts The Shirt Shop sold One morning × \(\frac{1}{5}\)
= 15 × \(\frac{1}{5}\)
= 3 × 1
= 3.
Number of white T-shirts were sold = Number of T-shirts The Shirt Shop sold One morning – Number of gray T-shirts sold
= 15 – 3
= 12.

Question 10.
A chef bought some green and red peppers. She bought 18 green peppers, which was \(\frac{3}{4}\) of the total number.

a. How many red peppers did she buy?
Answer:
Number of red peppers she buys = 6.

Explanation:
Number of green peppers She bought = 18.
She bought 18 green peppers, which was \(\frac{3}{4}\) of the total number.
Let the total number of peppers she buys be X.
Number of green peppers She bought = Total number of peppers she buys × \(\frac{3}{4}\)
= 18 = X × \(\frac{3}{4}\)
=> 18 × \(\frac{4}{3}\) = X
=> 6 × 4 = X
=> 24 = X.
Number of red peppers she buys = Total number of peppers she buys – Number of green peppers She bought
= 24 – 18
= 6.

b. How many peppers did she buy altogether?
Answer:
Total number of peppers she buys = 24.

Explanation:
Number of green peppers She bought = 18.
She bought 18 green peppers, which was \(\frac{3}{4}\) of the total number.
Let the total number of peppers she buys be X.
Number of green peppers She bought = Total number of peppers she buys × \(\frac{3}{4}\)
= 18 = X × \(\frac{3}{4}\)
=> 18 × \(\frac{4}{3}\) = X
=> 6 × 4 = X
=> 24 = X.

Question 11.
There were 25 melons in a box at the grocery store.
The store sold \(\frac{3}{5}\) of the melons.
How many melons were sold?
Answer:
Number of melons sold = 15.

Explanation:
Number of melons in a box at the grocery store = 25.
The store sold \(\frac{3}{5}\) of the melons.
=> Number of melons sold = Number of melons in a box at the grocery store × \(\frac{3}{5}\)
= 25 × \(\frac{3}{5}\)
= 5 × 3
= 15.

Question 12.
Ava read \(\frac{1}{4}\) of a book on Monday, and \(\frac{1}{5}\) of it on Tuesday. There are 80 pages in the book. How many pages did she read altogether on both days?
Answer:
Number of pages she read altogether on both days = 36.

Explanation:
Number of pages in the book = 80.
Ava read \(\frac{1}{4}\) of a book on Monday.
=> Number of pages Ava read on Monday = Number of pages in the book × \(\frac{1}{4}\)
= 80 × \(\frac{1}{4}\)
= 20 × 1
= 20.
Ava read \(\frac{1}{5}\) of it on Tuesday.
> Number of pages Ava read on Tuesday = Number of pages in the book × \(\frac{1}{5}\)
= 80 × \(\frac{1}{5}\)
= 16 × 1
= 16.
Number of pages she read altogether on both days = Number of pages Ava read on Monday + Number of pages Ava read on Tuesday
= 20 + 16
= 36.

Practice the problems of Math in Focus Grade 4 Workbook Answer Key Chapter 7 Practice 6 Rounding Decimals to score better marks in the exam.

Math in Focus Grade 4 Chapter 7 Practice 6 Answer Key Rounding Decimals

Fill in the missing number in each box.
Then round each decimal to the nearest tenth.

Example

8.14 rounded to the nearest tenth is 8.1

Question 1.

11.15 rounded to the nearest tenth is ____
Answer:
11.15 rounded to the nearest tenth is 11.20.

Explanation:
11.15 – 11.1 = 0.05
=> 11.15 + 0.05 = 11.20.

Question 2.

0.96 rounded to the nearest tenth is ____
Answer:
0.96 rounded to the nearest tenth is 1.00.

Explanation:
0.96 + 0.04 = 1.00.

Question 3.

7.53 rounded to the nearest tenth is ____
Answer:
7.53 rounded to the nearest tenth is 7.50.

Explanation:
7.50   7.51   7.52  7.53   7.54   7.55   7.56   7.57   7.58   7.59   7.60.

Round each measure.
Question 4.
Ryan’s mass is 44.69 kilograms.
Round his mass to the nearest tenth of a kilogram. ____ kilograms is about ____ kilograms.
Answer:
Nearest tenth of a kilogram = 44.70.
44.69 kilograms is about 45 kilograms.

Explanation:
Number of kilograms Ryan’s mass = 44.69.
Nearest tenth of a kilogram = 44.70.
44.69 kilograms is about 45 kilograms.

Question 5.
Susan’s height is 1.72 meters.
Round her height to the nearest tenth of a meter.
___ meters is about ___ meters.
Answer:
Nearest tenth of a meter = 1.80.
1.72 meters is about 2.00 meters.

Explanation:
Susan’s height is 1.72 meters.
Nearest tenth of a meter = 1.80.
1.72 meters is about 2.00 meters.

Question 6.
The distance between Chong’s home and his school is 5.95 miles. Round the distance to the nearest tenth of a mile.
___________ miles is about ___________ miles.
Answer:
Nearest tenth of a mile =  6.00.
5.95 miles is about 6.00 miles.

Explanation:
The distance between Chong’s home and his school is 5.95 miles.
Nearest tenth of a mile =  6.00.
5.95 miles is about 6.00 miles.

Question 7.
1 inch is equal to 2.54 centimeters.
Round 2.54 to the nearest tenth of a centimeter.
___ centimeters is about ___ centimeters.
Answer:
Nearest tenth of a 2.54 centimeter = 2.60.
2.54 centimeters is about 3.00 centimeters.

Explanation:
1 inch is equal to 2.54 centimeters.
Nearest tenth of a 2.54 centimeter = 2.60.
2.54 centimeters is about 3.00 centimeters.

Question 8.
1 pound is approximately equal to 0.45 kilogram. Round 0.45 to the nearest tenth of a kilogram. ___ kilogram is about ___ kilogram.
Answer:
Nearest tenth of a 0.45 kilogram = 0.50.
0.45 kilogram is about 0.50 kilogram.

Explanation:
1 pound is approximately equal to 0.45 kilogram.
Nearest tenth of a 0.45 kilogram = 0.50.
0.45 kilogram is about 0.50 kilogram.

Round each decimal to the nearest whole number and the nearest tenth.

Question 9.

Answer:

Explanation:
Nearest whole number of 3.49 = 3.00.
Nearest tenth of 3.49 = 3.50.

Question 10.

Answer:

Explanation:
Nearest whole number of 5.65 = 6.00.
Nearest tenth of 5.65 = 5.70.

Question 11.

Answer:

Explanation:
Nearest whole number of 4.13 = 4.00.
Nearest tenth of 4.13 = 4.10.

Question 12.

Answer:

Explanation:
Nearest whole number of 4.99 = 5.00.
Nearest tenth of 4.99 = 5.00.