# Math in Focus Grade 5 Chapter 5 Answer Key Algebra

Go through the Math in Focus Grade 5 Workbook Answer Key Chapter 5 Algebra to finish your assignments.

## Math in Focus Grade 5 Chapter 5 Answer Key Algebra

Math Journal

John’s solutions to the following problems are as shown. Identify and explain the mistakes John has made. Then give the correct solution.

Question 1.
4w + 12w – 10 = 16w – 10
= 6 w
4w + 12w – 10 = 16w – 10
Explanation:
John has made a mistake in subtracting number from a variable type of number. So, the correct solution is 16w – 10.

Question 2.
20p – 2p + 4p = 20p – 6 p
= 14p
20p – 2p + 4p = 24p – 2p = 22p
Explanation:
John has made a mistake in the order of subtraction and additions. First we should add all the numbers and then subtract the numbers. So, the correct solution is 22p.

Question 3.
6 ÷ q = $$\frac{q}{6}$$
6 ÷ q = 6/q
Explanation:
John has made a mistake in putting the numerator and denominator of a division.
The number before the division symbol (÷) should be consider as numerator.
The number after the division symbol (÷) should be consider as denominator.
So, the correct solution is 6/q.

Question 4.
Clarissa bought 3 cartons of milk for y cents each. She gave the cashier $10. How much change did she receive? Express your answer in terms of y. Answer: 3 × y = 3y 3 cartons of milk cost 3y cents.$1 = 100 cents
So, $10 = 1,000 cents Hence, Clarissa received (1,000 – 3y) cents in change. Put On Your Thinking Cap! Challenging Practice Wendy bought 7 handbags. Each handbag costs the same amount. She paid the cashier$100 and received g dollars in change.

a. What was the cost of each handbag in terms of g?
Total money paid to cashier is $100. Total number of handbags bought = 7 Total change received = g$
So, cost of 7 handbags = (100-g)$Cost of each handbag = (100-g)/7$

b. If the price of each handbag was more than $1 0, what is the least possible value of g? (Assume that the cost of each handbag is a whole number.) Answer: Assume that each handbag costs 10$, then change given is (100-(7×10)) =(100-70)$= 30$
Assume that each handbag costs 12$, then change given is (100-(7×12)) =(100-84)$ = 16$Assume that each handbag costs 14$, then change given is (100-(7×14)) =(100-98)$= 2$
So, the least possible value of g is 2.

Put On Your Thinking Cap

Problem Solving

There are 40 pupils in a class. There are x more girls than boys.

a. How many boys are there in terms of x?