Go through the Math in Focus Grade 5 Workbook Answer Key Chapter 3 Practice 7 Real-World Problems: Fractions and Mixed Numbers to finish your assignments.
Math in Focus Grade 5 Chapter 3 Practice 7 Answer Key Real-World Problems: Fractions and Mixed Numbers
Solve. Show your work.
Question 1.
Elena has 1 2 pieces of banana bread. She gives an equal amount of banana bread to 5 friends. How many pieces of banana bread does she give each friend?
Answer:
2\(\frac{2}{5}\) pieces of banana bread that she give each friend
Explanation:
Elena has 1 2 pieces of banana bread.
She gives an equal amount of banana bread to 5 friends.
12 is shared between 5 friends
12 ÷ 5
\(\frac{12}{5}\) =
\(\frac{10}{5}\) + \(\frac{2}{5}\)
= 2 + \(\frac{2}{5}\)
2\(\frac{2}{5}\) pieces of banana bread that she give each friend
Question 2.
A utility bill shows that a household used 2,001 gallons of water in a 5-day period. What was the average amount of water used by the household each day?
Answer:
400 gallons
Explanation:
A utility bill shows that a household used 2,001 gallons of water in a 5-day period.
2000 ÷ 5 = 400
400 gallons was the average amount of water used by the household each day
Question 3.
A ball of string is 50 yards long. A shipper uses 5 yards of string to tie packages. The remaining string is then cut into 7 equal pieces. What is the length of each of the 7 pieces of string?
Answer:
50 – 5 = 45
45 ÷ 7 = 6.4
the length of each of the 7 pieces of string = 6.4
Explanation:
A ball of string is 50 yards long.
A shipper uses 5 yards of string to tie packages.
50 – 5 = 45
The remaining string is then cut into 7 equal pieces.
7 x 6 = 42
42 is the length of each of the 7 pieces of string
Question 4.
Steve picks 55 pounds of pears. He packs an equal amount of pears into 6 bags. He then has 4 pounds of pears left. What is the weight of pears in each bag?
Answer:
10.1 is the weight of pears in each bag
Explanation:
Steve picks 55 pounds of pears.
He packs an equal amount of pears into 6 bags.
55 ÷ 6 = 6.1
9 x 6 = 54
He then has 4 pounds of pears left.
6.1 + 4 = 10.1
10.1 is the weight of pears in each bag
Question 5.
Jeremy puts an empty container under a leaking faucet. In the first hour, \(\frac{3}{8}\) quart of water collects. In the second hour, \(\frac{1}{6}\) quart of water collects. How much water collects in the container in the two hours?
Answer:
\(\frac{13}{24}\) water collects in the container in the two hours
Explanation:
Jeremy puts an empty container under a leaking faucet.
In the first hour, \(\frac{3}{8}\) quart of water collects.
In the second hour, \(\frac{1}{6}\) quart of water collects.
\(\frac{3}{8}\) + \(\frac{1}{6}\)
\(\frac{13}{24}\) water collects in the container in the two hours
Solve. Show your work.
Question 6.
Arnold buys \(\frac{8}{9}\) pound of ground turkey. He uses \(\frac{3}{4}\) pound or the ground turkey to make meatballs. How many pounds of ground turkey are left?
Answer:
\(\frac{5}{36}\)
Explanation:
Arnold buys \(\frac{8}{9}\) pound of ground turkey.
He uses \(\frac{3}{4}\) pound or the ground turkey to make meatballs.
\(\frac{8}{9}\) – \(\frac{3}{4}\) = \(\frac{5}{36}\)
\(\frac{5}{36}\) pounds of ground turkey are left
Question 7.
A snail is at the bottom of a well. In the first 1 0 minutes, the snail climbs 23\(\frac{7}{23}\) inches. in the next 10 minutes, it climbs 19\(\frac{5}{6}\) inches. How far is the snail from the bottom of the well after 20 minutes?
Answer:
43\(\frac{19}{138}\)
Explanation:
A snail is at the bottom of a well. In the first 1 0 minutes, the snail climbs 23\(\frac{7}{23}\) inches.
in the next 10 minutes, it climbs 19\(\frac{5}{6}\) inches.
23\(\frac{7}{23}\) + 19\(\frac{5}{6}\) = 43\(\frac{19}{138}\)
43\(\frac{19}{138}\) far is the snail from the bottom of the well after 20 minutes
Solve. Show your work
Question 8.
Johnny is jogging along a track. He has already jogged 1\(\frac{2}{3}\) miles. He plans to jog a total of 3\(\frac{1}{4}\) miles. How many miles does he have left to jog?
Answer:
4\(\frac{11}{12}\)
Explanation:
Johnny is jogging along a track.
He has already jogged 1\(\frac{2}{3}\) miles.
He plans to jog a total of 3\(\frac{1}{4}\) miles.
4\(\frac{11}{12}\) miles that he have left to jog