Practice the problems of Math in Focus Grade 7 Workbook Answer Key Chapter 4 Lesson 4.1 Understanding Equivalent Equations to score better marks in the exam.

## Math in Focus Grade 7 Course 2 A Chapter 4 Lesson 4.1 Answer Key Understanding Equivalent Equations

### Math in Focus Grade 7 Chapter 4 Lesson 4.1 Guided Practice Answer Key

**Copy and complete to state whether each pair of equations are equivalent equations. Give a reason for your answer.**

Question 1.

x – 3 + 4x = 5 and 5x = 2

x – 3 + 4x = 5

5x – 3 = 5 Group like terms.

5x – 3 + = 5 + Add to both sides.

5x = Simplify.

x – 3 + 4x = 5 be rewritten as 5x = 2.

So, the equations have solutions and are

Answer:

No, they are not equivalent equations.

Explanation:

Given 1st equation, x – 3 + 4x = 5

It can also be written as 5x – 3 =5

Add 3 to both sides, 5x – 3 + 3 = 5 + 3

5x = 8

So, equation x – 3 + 4x = 5 cannot be written as 5x = 2

Question 2.

x + 7 = 12 and 2x = 10

First solve x + 7 = 12.

x + 7 = 12

x + 7 – = 12 – Subtract from both sides.

x = Simplify.

Then check to see if is the solution of the equation 2x = 10.

If x = , 2x = 2 • Substitute for x.

= a solution.

Because the equations have the solution, they are equations.

Answer:

Yes, Both are equivalent equations.

Explanation:

First, let’s solve x + 7 = 12

Subtract 7 on both sides.

x + 7 – 7 = 12 -7

x = 5

Lets consider second equation 2x = 10

substitute x= 5 which we got by solving the 1st equation in the 2nd equation.

2.(5) = 10

Hence proved.

Question 3.

1.2x = 2.4 and x – 6 = 8

First solve x – 6 = 8.

x – 6 = 8

x – 6 + = 8 + Add to both sides,

x = Simplify.

Then check to see if is the solution of the equation 1.2x = 2.4.

If x = , 1.2x = 1.2 • Substitute for x.

= a solution.

Because the equations have solutions, they are equations.

Answer:

No, they are not equivalent equations.

Explanation:

First, lets consider x – 6 = 8

Add 6 on both sides

x – 6 + 6 = 8 + 6

x = 14

Lets substitute x = 14 in the first equation.

1.2 x = 2.4

1.2(14) = 16.8

Both the equations are not equivalent equations.

Question 4.

\(\frac{2}{5}\)x = 4 and x = 10.

If x = 10, \(\frac{2}{5}\)x = \(\frac{2}{5}\) • 10 Substitute 10 for x.

= a solution.

Because the equations have the solution, they are equations.

Answer:

Yes, both the equations have the same solution, they are equivalent equations.

Explanation:

Let’s consider first equation, (2/5)x =4

Let us substitute the second equation, x =10 in first equation.

(2/5) × 10 = 4

Hence proved.

Both the equations have the same solution, they are equivalent equations.

### Math in Focus Course 2A Practice 4.1 Answer Key

**Tell whether each pair of equations are equivalent. Give a reason for your answer.**

Question 1.

2x = 4 and 4x + 5 = 13

Answer:

Yes, Both the equations are equivalent.

Explanation:

Let us consider second equation, 4x + 5 = 13

Subtract 5 on both sides.

4x + 5 – 5 = 13 – 5

4x = 8

x = 8 ÷ 4

x = 2

Substitute x=2 in the first equation, 2x = 4

2(2) = 4

Hence proved.

Both the equations are equivalent.

Question 2.

-2x + 9 = 7 and —2x = 2

Answer:

No, both the equations are not equivalent.

Explanation:

Lets solve the first equation, -2x + 9 = 7

Subtract 9 on both sides.

-2x + 9 – 9 = 7 – 9

-2x = -2

The second equation is -2x = 2

So, both the equations are not equivalent.

Question 3.

5x – 4 + 3x = 8 and 8x = 12

Answer:

Both are equivalent equations.

Explanation:

Lets us consider first equation, 5x – 4 + 3x = 8

8x – 4 = 8

8x = 8 + 4

8x = 12

As we derived second equation from the first equation, both are equivalent equations.

Question 4.

\(\frac{3}{4}\)x – 7 = 2 and x = 12

Answer:

Yes, both are equivalent equations.

Explanation:

Let us consider first equation, (3/4)x = 2

Substitute, the second equation, x = 12 in the first equation.

(3/4)(12) – 7 = (3).(3) – 7

=9 – 7

=2

Hence proved. Both are equivalent equations.

**Match each equation with an equivalent equation.**

Answer:

5 – d

6 – c

7 – e

8 – a

9 – g

10 – f

11 – b

Explanation:

5. 0.5x + 1 = 1.5

0.5x = 1.5 – 1 = 0.5

x = 0.5 ÷ 0.5

x = 1

We can match 5th equation with equation (d) on the other side.

6. 9 + 3.5x = 16

Let us solve the equation

3.5x = 16 – 9

3.5x = 7

x = 7 ÷ 3.5

x = 2

We can match the equation (3/2)x = 3

x = 3 × (2/3)

x = 2

Hence both are same.

7. (4/5)x =4

4x = 20

x =5

We can match 7th equation with equation (e) on the other side.

2x =10

x =5

Hence Matched.

8. 2x + (1/2) = (7/2)

2x = (7/2) – (1/2)

2x = (6/2)

2x = 3

x = 3/2

As option (a) is 6x =9

It can be also written as 3/2 as both are dividends of 3.

9. x – 8.3 = 1.3

x = 1.3 + 8.3

x = 9.6

Option (g) is (1/2)x = 4.8

x =9.6

Hence matched.

10. 13.9 = 2.5x

x = 13.9 ÷ 2.5

x = 5.56

Option (f) is 1.2 + x = 6.76

x = 6.76 – 1.2

x =5.56

Hence proved.

11. 4x = (4/9)

x = 1/9

We can match with option (b).

(3/5)x = (1/15)

x = (1/9)

**Solve.**

Question 12.

Math Journal Max was asked to write to \(\frac{2}{3}\)x = 3 – x. He wrote the following:

\(\frac{2}{3}\)x = 3 – x

\(\frac{2}{3}\)x ∙ 3 = 3 ∙ 3 – x

2x = 9 – x

He concluded that \(\frac{2}{3}\)x = 3 – x and 2x = 9 \(\frac{2}{3}\) x are equivalent equations. Do you agree with his conclusion? Give a reason for your answer.

Answer:

No, I don’t agree with Max, both are not equivalent equations.

Explanation:

Let us consider first equation, (2/3)x = 3 – x

2x = 9 -3x (Max gave the equation 2x = 9 – x which is wrong, if we multiplied 3 on both sides not only it is multiplied with 3 it is also multiplies with x. so it is 2x = 9 -3x)

5x = 9

x = 9/5

x = 1.8

The second equation, 9(2/3)x =2x

substitute x =1.8 in the second equation

2 (1.8) = 9(2/3)(1.8)

3.6 = 10.8

Hence the both the equations are not equivalent.