Practice the problems of Math in Focus Grade 6 Workbook Answer Key Chapter 7 Lesson 7.1 Writing Algebraic Expressions to score better marks in the exam.

## Math in Focus Grade 6 Course 1 A Chapter 7 Lesson 7.1 Answer Key Writing Algebraic Expressions

### Math in Focus Grade 6 Chapter 7 Lesson 7.1 Guided Practice Answer Key

**Write an algebraic expression for each of the following.**

Question 1.

The sum of x and 10

Answer:

x + 10

Explanation:

x + 10 is an algebraic expression in terms of x.

x and 10 are the terms of expression.

Question 2.

The difference “7 less than y”

Answer:

y – 7

Explanation:

y – 7 is an algebraic expression in terms of x.

y and 7 are the terms of expression.

Question 3.

Jim is now z years old.

a) His brother is 4 years older than Jim. Find his brother’s age in terms of z.

Answer:

Jim’s brothers age is = z+4

Explanation:

Jim brother is 4 years older than Jim.

His brother’s age in terms of z.

z + 4

b) His sister is 3 years younger than Jim. Find his sister’s age in terms of z.

Answer:

Jim’s sister’s are is = z – 3

Explanation:

Jim sister is 3 years younger than Jim.

His sister’s age in terms of z.

z – 3

Question 4.

The product of z and 6

Answer:

z x 6

Explanation:

x x 6 is an algebraic expression in terms of x.

x and 6 are the terms of expression.

Question 5.

The quotient of w and 8

Answer:

\(\frac{w}{8}\)

Explanation:

\(\frac{w}{8}\) is an algebraic expression in terms of x.

w and 8 are the terms of expression.

Question 6.

Mia bought a pair of shoes for p dollars. She also bought a dress that cost 5 times as much as the shoes, and a belt that cost \(\frac{1}{4}\) of the price of the shoes.

a) Find the cost of the dress in terms of p.

Answer:

5p

Explanation:

a pair of shoes for p dollars

a dress that cost 5 times shoes = 5p

b) Find the cost of the belt in terms of p.

Answer:

\(\frac{p}{4}\)

Explanation:

a belt that cost \(\frac{1}{4}\) of the price of the shoes.

the cost of the belt = \(\frac{p}{4}\)

### Math in Focus Course 1A Practice 7.1 Answer Key

**Write an algebraic expression for each of the following.**

Question 1.

The sum of 4 and p

Answer:

p + 4

Explanation:

The sum of 4 and p is p + 4

p + 4 is an algebraic expression in terms of p.

p and 4 are the terms of expression.

Question 2.

The difference “8 less than q”

Answer:

q – 8

Explanation:

The difference “8 less than q” is q – 7

q – 7 is an algebraic expression in terms of q.

q and 7 are the terms of expression.

Question 3.

The product of 3 and r

Answer:

3 x r

Explanation:

The product of 3 and r is 3r

3 x r is an algebraic expression in terms of r.

r and 3 are the terms of expression.

Question 4.

The quotient of s and 5

Answer:

\(\frac{s}{5}\)

Explanation:

The quotient of s and 5 is \(\frac{s}{5}\)

\(\frac{s}{5}\) is an algebraic expression in terms of s.

s and 5 are the terms of expression.

Question 5.

Cheryl is now x years old.

a) Her father is 24 years older than Cheryl. Find her father’s age in terms of x.

Answer:

x + 24

Explanation:

Cheryl father is 24 years older than Cheryl.

Her father’s age in terms of x = x + 24

x + 24 is an algebraic expression.

b) Her brother is 2 years younger than Cheryl. Find her brother’s age in terms of x.

Answer:

x – 2

Explanation:

Cheryl brother is 2 years younger than Cheryl.

Her brother’s age in terms of x = x – 24

Here, x – 2 is the algebraic expression.

c) Her sister is twice as old as Cheryl. Find her sister’s age in terms of x.

Answer:

2x

Explanation:

Cheryl sister is twice as old as Cheryl.

Her sister’s age in terms of x = 2x

x = twice the age of her sister.

d) Her cousin is \(\frac{1}{3}\) Cheryl’s age. Find her cousin’s age in terms of x.

Answer:

\(\frac{x}{3}\)

Explanation:

Cheryl cousin is \(\frac{1}{3}\) Cheryl’s age.

Her cousin’s age in terms of x.

x\(\frac{1}{3}\) = \(\frac{x}{3}\)

Question 6.

Multiply k by 5, and then add 3 to the product.

Answer:

(k x 5) + 3

Explanation:

Multiply k by 5 = 5k

then add 3 to the product = (k x 5) + 3 = 5k + 3

Question 7.

Divide m by 7, and then subtract 4 from the quotient.

Answer:

\(\frac{m}{7}\) – 4

Explanation:

Divide m by 7 = \(\frac{m}{7}\)

then subtract 4 from the quotient.

\(\frac{m}{7}\) – 4

Question 8.

Divide j by 9, and then multiply the quotient by 2.

Answer:

\(\frac{j}{9}\) x 2

Explanation:

Divide j by 9 = \(\frac{j}{9}\)

then multiply the quotient by 2

\(\frac{j}{9}\) x 2

Question 9.

The sum of \(\frac{1}{3}\) of z and \(\frac{1}{5}\) of z

Answer:

\(\frac{z}{3}\) + \(\frac{z}{5}\)

Explanation:

\(\frac{1}{3}\) x z + \(\frac{1}{5}\) x z

= \(\frac{z}{3}\) + \(\frac{z}{5}\)

**Solve.**

Question 10.

Jeremy bought 5 pencils for w dollars. Each pen costs 35ct more than a Write an algebraic expression for each of the following in terms of w.

a) The cost, in dollars, of a pen

Answer:

\(\frac{w}{5}\) + 35

Explanation:

Jeremy bought 5 pencils for w dollars.

5 pencils = w dollars

Each pen costs 35ct more than a.

An algebraic expression for each of the following in terms of w.

\(\frac{w}{5}\) + 35

cost of one pen = \(\frac{w}{5}\) + 35 cents

b) The number of pencils that Jeremy can buy with $20

Answer:

\(\frac{100}{w}\)

Explanation:

Jeremy bought 5 pencils for w dollars.

5 pencils = w dollars

The number of pencils that Jeremy can buy with $20

\(\frac{20}{1}\)/ \(\frac{w}{5}\)

\(\frac{20}{1}\) x \(\frac{5}{w}\)

\(\frac{100}{w}\)

Question 11.

The figure shown is formed by a rectangle and a square. Express the area of the figure in terms of x.

Answer:

x(7 + 9)

Explanation:

the area of the figure in terms of x

length of rectangle = 7cm

length of square = 3cm

x X 7 + 3 x 3

x X 7 + 9