Practice the problems of Math in Focus Grade 4 Workbook Answer Key Chapter 6 Practice 6 Renaming Whole Numbers when Adding and Subtracting to score better marks in the exam.

## Math in Focus Grade 4 Chapter 6 Practice 6 Answer Key Renaming Whole Numbers when Adding and Subtracting Fractions

**Fill in the missing numerators.**

Example

Question 1.

Answer:

Explanation:

3 = 2\(\frac{6}{6}\) = 2 + 1.

= 1\(\frac{12}{6}\) = 1 + (12)6 = 1 + 2.

= \(\frac{18}{6}\)

Question 2.

Answer:

Explanation:

2\(\frac{7}{9}\) = 1\(\frac{16}{9}\)

= \(\frac{25}{9}\)

**Add. Express each answer as a mixed number in simplest form.**

Question 3.

\(\frac{4}{9}\) + \(\frac{2}{3}\)

Answer:

\(\frac{4}{9}\) + \(\frac{2}{3}\) = 13 ÷ 9 or \(\frac{13}{9}\)

Explanation:

\(\frac{4}{9}\) + \(\frac{2}{3}\)

= (4 + 6) ÷ 9

= 13 ÷ 9 or \(\frac{13}{9}\)

Question 4.

\(\frac{1}{6}\) + \(\frac{11}{12}\)

Answer:

\(\frac{1}{6}\) + \(\frac{11}{12}\) = 13 ÷ 12 or \(\frac{11}{12}\)

Explanation:

\(\frac{1}{6}\) + \(\frac{11}{12}\)

= (2 + 11) ÷ 12

= 13 ÷ 12 or \(\frac{11}{12}\)

Question 5.

\(\frac{1}{4}\) + \(\frac{3}{8}\) + \(\frac{3}{4}\)

Answer:

\(\frac{1}{4}\) + \(\frac{3}{8}\) + \(\frac{3}{4}\) = 11 ÷ 8 or \(\frac{11}{8}\)

Explanation:

\(\frac{1}{4}\) + \(\frac{3}{8}\) + \(\frac{3}{4}\)

= (2 + 3) ÷ 8 + \(\frac{3}{4}\)

= \(\frac{5}{8}\) + \(\frac{3}{4}\)

= [5 + 6] ÷ 8

= 11 ÷ 8 or \(\frac{11}{8}\)

Question 6.

\(\frac{4}{5}\) + \(\frac{7}{10}\) + \(\frac{9}{10}\)

Answer:

\(\frac{4}{5}\) + \(\frac{7}{10}\) + \(\frac{9}{10}\) = 12 ÷ 5 or \(\frac{12}{5}\)

Explanation:

\(\frac{4}{5}\) + \(\frac{7}{10}\) + \(\frac{9}{10}\)

= (8 + 7) ÷ 10 + \(\frac{9}{10}\)

= \(\frac{15}{10}\) + \(\frac{9}{10}\)

= (15 + 9) ÷ 10

= \(\frac{24}{10}\)

= 12 ÷ 5 or \(\frac{12}{5}\)

**Subtract. Express each answer as a mixed number in simplest form.**

Example

2 – \(\frac{1}{3}\)

Method 1

2 – \(\frac{1}{3}\) = \(\frac{2}{1}\) – \(\frac{1}{3}\)

= \(\frac{6}{3}\) – \(\frac{1}{3}\)

= \(\frac{5}{3}\) = 1\(\frac{2}{3}\)

Metgod 2

2 – \(\frac{1}{3}\) = 1\(\frac{3}{3}\) – \(\frac{1}{3}\)

= 1\(\frac{2}{3}\)

Question 7.

3 – \(\frac{5}{6}\) – \(\frac{1}{3}\)

Answer:

3 – \(\frac{5}{6}\) – \(\frac{1}{3}\) = \(\frac{5}{2}\)

Explanation:

3 – \(\frac{5}{6}\) – \(\frac{1}{3}\)

= 3 – [(5 – 2) ÷ 6]

= 3 – \(\frac{3}{6}\)

= (18 – 3) ÷ 6

= \(\frac{15}{6}\)

= \(\frac{5}{2}\)

Question 8.

2 – \(\frac{1}{4}\) – \(\frac{1}{4}\)

Answer:

2 – \(\frac{1}{4}\) – \(\frac{1}{4}\) = 2.

Explanation:

2 – \(\frac{1}{4}\) – \(\frac{1}{4}\)

= 2 – (0)

= 2.

Question 9.

2 – \(\frac{2}{7}\) – \(\frac{3}{14}\)

Answer:

2 – \(\frac{2}{7}\) – \(\frac{3}{14}\) = \(\frac{27}{14}\)

Explanation:

2 – \(\frac{2}{7}\) – \(\frac{3}{14}\)

= 2 – [(4 – 3) ÷ 14]

= 2 – \(\frac{1}{14}\)

= (28 – 1) ÷ 14

= \(\frac{27}{14}\)

Question 10.

3 – \(\frac{7}{10}\) – \(\frac{3}{4}\)

Answer:

3 – \(\frac{7}{10}\) – \(\frac{3}{4}\) = \(\frac{61}{20}\)

Explanation:

3 – \(\frac{7}{10}\) – \(\frac{3}{4}\)

= 3 – {[(2 × 7) – (3 × 5)] ÷ 20}

= 3 – [(14 – 15) ÷ 20]

= 3 – (-1 ÷ 20)

= 3 + \(\frac{1}{20}\)

= (60 + 1) ÷ 20

= \(\frac{61}{20}\)