Go through the Math in Focus Grade 5 Workbook Answer Key Chapter 5 Practice 5 Real-World Problems: Algebra to finish your assignments.

## Math in Focus Grade 5 Chapter 5 Practice 5 Answer Key Real-World Problems: Algebra

**Solve. Show your work.**

Question 1.

Raul has 5 boxes of golf balls. Each box contains y golf balls. His father gives him another 8 golf balls.

a. Find the total number of golf balls Raul has in terms of y.

Answer:

Number of boxes of golf balls Raul has = 5

As each box contains ‘y’ balls, total number of balls Raul has = 5y

Number of balls given by Raul’s father = 8

So, total number of golf balls does Raul has = 5y+8

b. If y = 4, how many golf balls does Raul have altogether?

Answer:

Total number of golf balls Raul has = 5y+8

If y=4, then total number of golf balls Raul has = (5×4)+8 = 20+8 = 28

So, Raul altogether has 28 balls.

Question 2.

Glenda bought z containers of laundry detergent at $9 each. She gave the cashier $50.

a. Find the change Glenda received in terms of z.

Answer:

Total number of laundry detergent containers bought = z

Cost of all containers bought = (9×z) $

Cash given to cashier = 50 $

Change received by Glenda = [50 – (9×z)] $

b. If z = 3, how much change did Glenda receive?

Answer:

If z=3. then total change received = [50-(9×3)] $ = [50-27]$ = 23$

Question 3.

Garrett is w years old. His mother is 4 times his age. His father is 3 years older than his mother.

a. How old is Garrett’s father in terms of w?

Answer:

Age of Garrett = w years

Age of Garrett’s mother = (4×w) years

Age of Garrett’s father = [(4×w)+3] years

b. If w = 9, how old is Garrett’s father?

Answer:

Age of Garrett’s father = [(4×w)+3] years

If w=9, then age of Garrett’s father = [(4×9)+3] = 39 years

Question 4.

An office manager bought 16 boxes of pens, each containing m pens. Workers took 10 pens from the supply room.

a. How many pens were left? Give your answer in terms of m.

Answer;

Total number of boxes of pens bought = 16

Number of pens each box contains = m

So, total number of pens bought = 16×m

Number of pens workers took from supply room = 10

So. then number of pens left = total number of pens – pens taken by workers

=(16×m)-10

b. If m = 5, how many pens were left in the supply room?

Answer:

Total number of pens left in supply room = (16×m)-10

If m=5, then total number of pens left = (16×5)-10 = 80-10= 70

**Solve. Show your work.**

Question 5.

Sarah has a box containing x ribbons and 4 extra ribbons. Jill has 1 2 ribbons.

a. Express the number of ribbons that Sarah has in terms of x.

Answer:

Number of ribbons Sarah has in box = x

Number of extra ribbons Sarah has = 4

So, total number of ribbons Sarah has= x+4

b. For what value of x will Sarah and Jill have the same number of ribbons?

Answer:

Number of ribbons Sarah has = x+4

Number of ribbons Jill has = 12

If we need to have same number of ribbons for Sarah and Jill, then

x+4 =8

x=8-4 = 4

So, for the value of x as 4, Sarah and Jill have the same number of ribbons

Question 6.

Henry made (2y + 4) paper cranes. Elise made (3y – 9) paper cranes.

a. If y = 6, who would have made more paper cranes?

Answer:

If y=6,

Paper cranes made by Henry = (2y+4) = [(2×6)+4] = 12+4 = 16

Paper cranes made by Elise= (3y-9) = [(3×6)-9] = 18-9 = 9

b. For what value of y will they have made the same number of paper cranes?

Answer:

Number of paper cranes Henry has = 2y+4

Number of paper cranes Elise has = 3y-9

If we need to have same number of paper cranes for Henry and Elise, then

3y-9 = 2y+4

3y-2y = 4+9

y=13

So, for the value of y as 13, Henry and Elise will have the same number of paper cranes

**Solve. Show Your Work**

Question 7.

Mary has y yards of fabric. She used 2 yards to sew a skirt. She used the remaining fabric to make 5 jackets.

a. Find the amount of material that was used to make each jacket in terms of y.

Answer:

Total number of yards of fabric = y

Total yards used to sew a skirt = 2

So, total number of yards left = y-2

Number of jackets made with remaining fabric = 5

So, amount of material that was used to make each jacket = (y-2)/5

b. If she has 17 yards of fabric, how much material was used for each jacket?

Answer:

If y=17, then material used for each jacket = (y-2)/5 = (17-2)/5 = 15/5 = 3

Question 8.

A magazine costs half as much as a book. The book costs p dollars. A pen costs $2 more than the magazine.

a. How much does the pen cost in terms of p?

Answer:

Cost of book = p$

A magazine costs half as much as a book which implies a book is twice the cost of a magazine.

So, cost of magazine = 2p $

A pen costs $2 more than the magazine.

So, cost of pen = 2p$ + 2$ = (2p+2) $

b. If the book costs $5, how much does the pen cost?

Answer:

If book costs $5,

cost of pen = (2p+2) $ = [(2×5)+2] $ = (10+2) $ = 12$