Practice the problems of Math in Focus Grade 4 Workbook Answer Key Chapter 6 Fractions and Mixed Numbers to score better marks in the exam.

## Math in Focus Grade 4 Chapter 6 Answer Key Fractions and Mixed Numbers

**Math Journal**

Is the model correct? If not, explain why it is wrong. Draw the correct model.

Correct model:

Answer:

Explanation:

(2 ÷ 7 ) × 21 is wrong because 6 parts should be shaded not 3.

(2 ÷ 7 ) × 21 = 2 × 3 = 6.

**Put On Your Thinking Cap!
**

**Challenging Practice**

Question 1.

Show 1\(\frac{1}{4}\)– shaded, if 1 whole is made up of 4 squares. Some of the shading has been done for you.

Answer:

Explanation:

1\(\frac{1}{4}\) of 4

= (5 ÷ 4) × 4

= 5.

Question 2.

Is the answer of 21 × \(\frac{2}{7}\) the same as that of 2 × \(\frac{21}{7}\)? Show your work.

Answer:

Yes, both the answers are same.

Explanation:

21 × \(\frac{2}{7}\) = 3 × 2 = 6.

2 × \(\frac{21}{7}\) = 2 × 3 = 6.

Question 3.

Write a fraction and a whole number that have the same product as the problem below.

8 × \(\frac{3}{4}\) = ___

____ × _____ = ___

Answer:

8 × \(\frac{3}{4}\) = 3 × \(\frac{8}{4}\) = 3 × 2 = 6.

Explanation:

8 × \(\frac{3}{4}\) = 2 × 3 = 6.

3 × \(\frac{8}{4}\) = 3 × 2 = 6.

**Put On Your Thinking Cap!
**

**Problem Solving**

Caroline places five poles A, B, C, D, and E in order along a straight line. The distance between poles A and D is 1 yard. The distance between poles B and C is the same as the distance between poles A and B.

Poles A and B are \(\frac{1}{5}\) yard apart.

The distance between D and E is \(\frac{7}{10}\) yard.

How far apart are poles B and E?

Answer:

Distance between poles B and E = 3 ÷ 2 or \(\frac{3}{2}\).

Explanation:

Distance between poles A and D = 1 yard.

The distance between poles B and C is the same as the distance between poles A and B.

=> Distance between poles B and C = Distance between poles A and B.

Let the distance between poles B and C be X.

Distance between poles A and B = \(\frac{1}{5}\) yard.

Distance between poles D and E = \(\frac{7}{10}\) yard.

Distance between poles A and B + Distance between poles B and C + Distance between C and D = Distance between poles A and D

= \(\frac{1}{5}\) + \(\frac{1}{5}\) + Distance between C and D = 1

= \(\frac{2}{5}\) + Distance between C and D = 1

= Distance between C and D = 1 – \(\frac{2}{5}\)

= Distance between C and D = (5 – 2) ÷ 5

= Distance between C and D = 3 ÷ 5 or \(\frac{3}{5}\) yard.

Distance between poles B and E = Distance between poles B and C + Distance between C and D + Distance between poles D and E

= \(\frac{1}{5}\) + \(\frac{3}{5}\) + \(\frac{7}{10}\)

= \(\frac{4}{5}\) + \(\frac{7}{10}\)

= (8 + 7) ÷ 10

= 15 ÷ 10

= 3 ÷ 2 or \(\frac{3}{2}\)